sin(3)+cos(3)sin(3)tan(3)3=0=−cos(3)=−1=−4+,∈ℤ=−12+3
sin(3x)+cos(3x) =0 sin(3x) =−cos(3x) tan(3x) =−1 3x =−
π
4
+kπ,k∈
Z
x =−
π
12
+
k
π
3
Since −<<
−
π
<
x
<
π
, −2≤≤3
−
2
≤
k
≤
3
. Thus, the solution set is
{−34,−512,−12,4,712,1112}
Answer:
4
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(6-(-2))/(3-1)
m=(6+2)/(2)
m=8/2
m=4
Take your graph and turn it counterclockwise 90°, 3 times (which equals 270°).
Let the horizontal line represent the x-axis and the vertical line represent the y-axis. What are the new coordinates of the image? J'(2, 6), M'(-1, 5)
Answer: C
Answer: 5.1
Step-by-step explanation:
pythagorean theorem: a^2+b^2=c^2
c^2-b^2=a^2 (switch around some things)
(14.9)^2 - (14)^2 = x^2 (insert values) c=14.9,b=14,a=x
222.01 - 196 = x^2
26.01 = x^2
5.1 = x
