The sides with the little stroke between the lines “B” and “E” are congruent to each other. Also, within the top of the triangles by the very tip of the triangle by “C” that are facing each other are congruent, and of course angle B and E are also congruent angles. I’ll show a picture so you can get a better understanding of what am exactly meaning. This is an AAS Triangle by the way. 1 side is congruent and 2 angles are congruent with this diagram. I really hope this answer and the picture helps!
-7.763 will be the total to the answer.
5= g-5
number 2. 43
hope this helps you
Answer:
Step-by-step explanation:
The best way to solve this problem is to prove that any norm defines a metric, and then proving that the supremum norm is, in fact, a norm.
<em>Let us prove that any norm defines a metric.</em>
Assume that is a norm in a linear space . Define
and let us prove that is a metric.
The first to axioms of metric are trivial:
- for all . Moreover, and if and only if .
- .
As usual, the triangular inequality is less simple, but not so hard in this case:
and this holds for every . Recall that from the definition of norm we already have a triangular inequality: .
Now, we are in conditions to prove that the supremum norm, is a norm.
<em>The supremum norm is a norm on </em>.
The supremum norm is defined as , where is a continuous function over the set . Next, we are going to prove the three axioms.
(N1): .
(N2):
(N3):
from here we get
Answer:
D
Step-by-step explanation:
D is the correct answer