(8/9)^2 is just 8/9 squared, or 8/9 * 8/9. This is 64/81, and cannot be reduced. This is therefore our answer.
To find is out put it like this 2 8
5 x
you multiple so 2 times what eduals 8 then you take that and multiply by 5
Answer:
The short answer is there isn’t.
Start by writing each of these as an expression:
x * y = 60
x + y = 7
Next, solve each for the same variable; in this case, y:
(x * y) / x = 60 / x
.: y = 60 / x
(x + y) - x = 7 - x
.: y = 7 - x
Next, replace y of the second expression to the first
y = 60 / x & y = 7 - x
.: 7 - x = 60 / x
Now, solve for x:
(7 - x) * x = (60 / x) * x
.: x * 7 - x^2 = 60
This is quadratic, so write it in the form of ax2 + bx + x = 0
(-1)x^2 + (7)x + (-60) = 0
.: a = -1, b = 7, c = -60
Finally solve for b:
x = (-b +- sqrt(b^2 - 4*a*c)) / 2a
.: x = (-7 +- sqrt(7^2 - 4*-1*-60)) / (2 * -1)
.: x = (-7 +- sqrt(49 - 240)) / -2
.: x = (-7 +- sqrt(-191)) / -2
The square root of a negative value is imaginary and thus there’s no real answer to this problem.
Answer:
140 ounces of water and 105 ounces of 35% salt solution.
Explanation:
Let 
be the ounces of water that need to be added and 
be the ounces of 35% solution that need to to be added.
We know that the total of ounces of water and of 35% solution must be 245 ounces:
35% of is the salt, and since no salt is added with addition of liters of water, this must be equal to the amount of salt in the final 15% solution:
we solve for and get:
We put this value into and solve for to get:
Thus we have 140 ounces of water and 105 ounces of 35% solution.
