The largest consecutive integers whose sum is less than 46 are x= 21 and x+1=22
Step-by-step explanation:
Let the integers be:
x and x+1
The sum of these integers is less than 46
Solving and finding value of x:
So, the integers will be less than 22.5
The largest numbers are: 21 and 22
So, the largest consecutive integers whose sum is less than 46 are x= 21 and x+1=22
Keywords: Finding integers
Learn more about finding integers at:
#learnwithBrainly
Based on the given parameters, the value of Rx is R18
<h3>How to determine the value of Rx?</h3>
The given parameters are:
Number of people = 25
Amount paid = Rx
Additional people of 5 = Amount paid being R3 less
The total amount paid is calculated using:
Total amount = Number of people * Amount paid
Substitute the known values in the above equation
Total amount = 25 * x
Total amount = (25 + 5) * (x - 3)
Substitute Total amount = (25 + 5) * (x - 3) in Total amount = 25 * x
(25 + 5) * (x - 3) = 25 * x
Evaluate the sum
30 * (x - 3) = 25 * x
Evaluate the products
30x - 90 = 25x
Collect like terms
30x - 25x = 90
Evaluate the like terms
5x = 90
Divide both sides by 5
x = 18
Hence, the value of Rx is R18
Read more about equations at:
brainly.com/question/2972832
#SPJ1
Answer:
-1
Step-by-step explanation:
Once we have an absolute value, we know that
It is 17 if you do the math and do the multiples of 187 and 578
When x = 1
5(1) = -y + 6
5 = -y + 6
y = 6 - 5 = 1
When x = 2
5(2) = -y + 6
10 = -y + 6
y = 6 - 10 = -4
When x = 3
5(3) = -y + 6
15 = -y + 6
y = 6 - 15 = -9
