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3 years ago

Given h(x) = -3x - 2 solve for x when h(x) = 1

Mathematics

2 answers:

valina [46]3 years ago

7 0

Answer:

The answer is (-5)

Step-by-step explanation:

h(x) = -3x – 2; h(x) = 1

h(1) = -3(1) – 2

h(1) = -3 – 2

h(1) = -5

Thus, The answer is (-5)

-TheUnknownScientist 72

solmaris [256]3 years ago

5 0

Answer:

-5

Step-by-step explanation:

h(x) = -3x - 2

h(x) = 1

[ just put '1' in place of every 'x' ]

-3(1) -2
= -3 -2
= -5 (answer)

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kvv77 [185]

Answer:

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Step-by-step explanation:

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Then you have x <= 3.

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3 years ago

Find the solution to the equation 3x + 1 = 6x + 1

Musya8 [376]

Answer:

x=0

Step-by-step explanation:

First, start by getting rid of your X values. You must take your lowest X value and find a way to move it to the other side. Our lowest X value is 3x, and it's currently being added to 1.

In order to move it, we must subtract it on both sides.

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Let's check

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This is a true statement

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3 years ago

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Brilliant_brown [7]

Answer:

$f(x)=\sqrt{x-1}$ -----> Graph C

$f(x)=\sqrt{x}$ -----> Graph A

$f(x)=\sqrt{x}-1$ -----> Graph B

$f(x)=-\sqrt{x}$ -----> Graph D

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Step-by-step explanation:

we have

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we know that

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Find the domain

we know that

The radicand must be greater than or equal to zero

$x\geq 0$

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to 0

The range is the interval -----> [0,∞)

All real numbers greater than or equal to 0

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Find the domain

we know that

The radicand must be greater than or equal to zero

$x\geq 0$

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to 0

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Find the domain

we know that

The radicand must be greater than or equal to zero

$x\geq 0$

The domain is the interval -----> [0,∞)

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All real numbers less than or equal to 0

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Find the domain

we know that

The radicand must be greater than or equal to zero

$x-1\geq 0$

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The domain is the interval -----> [1,∞)

All real numbers greater than or equal to 1

The range is the interval -----> (-∞,0]

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ziro4ka [17]

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