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2 years ago

Given h(x) = -3x - 2 solve for x when h(x) = 1

Mathematics

2 answers:

valina [46]2 years ago

7 0

Answer:

The answer is (-5)

Step-by-step explanation:

h(x) = -3x – 2; h(x) = 1

h(1) = -3(1) – 2

h(1) = -3 – 2

h(1) = -5

Thus, The answer is (-5)

<u>-TheUnknownScientist 72</u>

solmaris [256]2 years ago

5 0

Answer:

-5

Step-by-step explanation:

h(x) = -3x - 2

h(x) = 1

[ just put '1' in place of every 'x' ]

-3(1) -2
= -3 -2
= -5 (answer)

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2 years ago

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2 years ago

1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING

iogann1982 [59]

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$\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0$

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We can solve the recurrence exactly by substitution:

$a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0$

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2 years ago

What is the value of 5(a + b) when a=1 and b=6

lana [24]

Answer: 35

Step-by-step explanation:

We substitute a for 1 and b for 6.

5(1+6)=5(7)=35

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2 years ago