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VARVARA [1.3K]
2 years ago
7

Can someone tell me how??? i got this correct and i really dont know howww

Mathematics
1 answer:
vodomira [7]2 years ago
5 0

Answer:

It scientifically proven

Step-by-step explanation:

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Find the area of the triangle shown
Artemon [7]

Answer:

Area = 48m²

Step-by-step explanation:

S(ACB) = AB × AC/2

S(ACB) = 8 × 12/2 m²

S(ACB) = 48m²

Hope this helps and have a nice day

7 0
2 years ago
A box of breakfast tacos coat $12 and a contains 8 tacos how much dose each taco coast
Rom4ik [11]

Answer:

$1.50

Step-by-step explanation:

12/8 = 1.50

3 0
2 years ago
Read 2 more answers
Can someone solve this problem for me? Show me your steps to solve this problem as well.
AveGali [126]
\bf 3^x=81\qquad 
\begin{cases}
81=3\cdot 3\cdot 3\cdot 3\\
\qquad 3^4
\end{cases}\implies 3^x=3^4\implies x=4

if their base is the same, the exponents must also be the same for the equation to be true.
5 0
3 years ago
6. Write the general equation of a circle with the given information. *<br>(x + 4)2 + (y - 3)2 = 24​
trapecia [35]

I think the answer is

2x + 2y = 26

4 0
3 years ago
How much work is done in lifting a 1.4-kg book off the floor to put it on a desk that is 0.7 m high?
nalin [4]

Answer:

Step-by-step explanation:

Work is said to be done when a force applied to an object cause the body to move in a specified direction.

Work-done = Force * Distance

Since Force = mass * acceleration due to gravity

Work-done =  mass * acceleration due to gravity * distance

Given mass = 1.4kg, distance = 0.7m and g = 9.8m/s²

Workdone in lifting the book off the floor = 1.4*0.7*9.8

Workdone = 9.604Joules

- Similarly, work done in lifting a 21-lb weight book 6 ft off the ground is expressed using the same formula as above;

Given mass = 21-lb, g = 32ft/s² and distance = 6ft

Workdone = 21 * 32 * 6

Workdone = 4,032 lb-ft²/s²

Hence, work-done in lifting a 21-lb weight book 6 ft off the ground is  4,032 lb-ft²/s²

3 0
3 years ago
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