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2 years ago

5. An irregular pentagon is rotated 180° about the

Mathematics

1 answer:

elena-14-01-66 [18.8K]2 years ago

4 0

The answers are true true false

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the perimeter of a rectangle is 68ft the ratio of the length to the width iss 9:8 what are the dimensions of the rectangle

NikAS [45]

Answer:

Step-by-step explanation:

2 * L + 2 * W = 68

2*L = 2* 9x = 9x + 9x

2*W = 2*8x = 8x + 8x

Since the perimeter is 68

9x + 9x + 8x + 8x = 68

4 0

3 years ago

The length of a rectangle is x feet. Its width is (x-7) feet. Draw and label a rectangle to represent this situation. Then write

a_sh-v [17]

Answer:

Perimeter of rectangle:

$(4x - 14)\text{ feet}$

Step-by-step explanation:

We are given the following in the question:

Length of rectangle:

$x\text{ feet}$

Width of rectangle:

$(x-7)\text{ feet}$

Perimeter of rectangle:

$2\times \text{(Length + Width)}$

Expressions to calculate perimeter

$1. ~2((x) + (x - 7))\text{ feet}\\2.~2(2x-7)\text{ feet}\\3.~ 4x-14\text{ feet}$

The attached image shows the image of the rectangle.

3 0

3 years ago

Can anyone answer these?

Soloha48 [4]

Answer:

rod waves can give u the answer for that just play a some him

4 0

3 years ago

PLEASE HELP ITS URGENT

OlgaM077 [116]

The missing step in this proof is ∠BAC ≅ ∠BDE ⇒ answer D

Step-by-step explanation:

If two triangles are similar by SAS, then their corresponding angles are

equal and the 3rd corresponding sides have constant ratio

In the two triangles ABC and DBE:

∠ABC ≅ ∠DBE
$\frac{AB}{DB}=\frac{BC}{BE}$

Then the two triangles are similar

From similarity:

∠BAC ≅ ∠BDE

∠BCA ≅ ∠BED

∴ The missing step is ∠BAC ≅ ∠BDE

The missing step in this proof is ∠BAC ≅ ∠BDE

Learn more:

You can learn more about triangles in brainly.com/question/3451297

#LearnwithBrainly

8 0

3 years ago

Read 2 more answers

If y has moment-generating function m(t) = e 6(e t −1) , what is p(|y − µ| ≤ 2σ)?

Lostsunrise [7]

Since $\mathrm M_Y(t)=e^{6(e^t-1}$ , we know that $Y$ follows a Poisson distribution with parameter $\lambda=6$ .

Now assuming $\mu,\sigma$ denote the mean and standard deviation of $Y$ , respectively, then we know right away that $\mu=6$ and $\sigma=\sqrt6$ .

So,

$\mathbb P(|Y-\mu|\le2\sigma)=\mathbb P(6-2\sqrt6\le Y\le6+2\sqrt6)=\dfrac{66366}{175e^6}\approx0.940028$

6 0

4 years ago