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The figure (i) have a distance of 15.996 meters and a displacement of 13.892 meters and (ii) a distance of 480 centimeters and a displacement of 339.411 centimeters
<h3>How to find the distance and displacement in each trajectory</h3>
The distance is the sum of the lengths that form a trajectory and the displacement is the distance between the <em>initial</em> and <em>final</em> point of a trajectory. Then, we have the following results for each case:
Case I
Distance
d = 5 m + 0.5π · (7 m)
d ≈ 15.996 m
Displacement
D ≈ 13.892 m
Case II
Distance
d = 8 · (60 cm)
d = 480 cm
Displacement
D ≈ 339.411 cm
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The solution of the system of linear equation are (1, 7)
<h3>How to solve system of equation?</h3>3a + 6b = 45
2a - 2b = -12
multiply equation(ii) by 3
Therefore,
3a + 6b = 45
6a - 6b = -36
9a = 9
a = 1
Hence,
2(1) - 2b = -12
2 - 2b = -12
-2b = -12 - 2
- 2b = - 14
b = -14 / -2
b = 7
learn more on equation here: brainly.com/question/14070610
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