Question

Find the distance between P (2,2) and Q (5.5, 6.25)

Answer 1

Answer:

distance between them is 5.51 units.

Explanation:

                       $\boxed{distance =\sqrt{(x2 - x1)^2+(y2-y1)^2} }$

given coordinates:  P (2,2) and Q (5.5, 6.25)

using the formula:

$\boxed{distance =\sqrt{(5.5 - 2)^2+(6.25-2)^2} }$

$\boxed{distance =\sqrt{12.25+18.0625} }$

$\boxed{distance =\sqrt{30.3125} }$

$\boxed{distance = 5.51 }$