Revenue: R(x) = 100x
Profit: P(x)= 3100 + 9x + 0.1x2 <span>(0 ≤ x ≤ 500)
</span><span>equalize the two equations
</span>100x=3100 + 9x + 0.1x2
0.1x2-91x+3100=0
<span>using graphic tools
x1=35.447----35
x2=874
the domain is </span>(0 ≤ x ≤ 500)
the value from which there are profits is 35 <span>pairs of cleats
</span>
Revenue: R(x) = 100x --------100*35=$3500
Profit: P(x)= 3100 + 9x + 0.1x2 -------3100+9*35+0.1*(35)2=$3537.5
Profit > Revenue up to the amount of 35 pairs of cleats
Answer:
a. f(x) = 21 (20) +1 (25) = 445
b. The scenario is a function because each student just have to pay once.
<span>6*5.4*10^(-4)
=32.4*10^(-4)
move the decimal point, in scientific notation you only have a single digit with comma
=3.2*10^(-3)
so option A
to know if you have to increase or decrease the exponent you can write the intermediary steps out:</span>
32.4*10^(-4)=32.4/10^4=<span>(3.24*10)/(10*10^3)
reduce the fraction and you have the above solution
</span>
D because 6/20 is correct and the three wrong super wrong hope it helps