Answer:
Im so sorry but I have no idea
Step-by-step explanation:
Answer:
Denote the center of circle as O, the 2 endpoints of shaded segment as AB, then we have:
section OAB area = pi x radius^2 x (120/360) = pi x 6^2 x (1/3) = 37.7 (cm2)
Considering triangle OAB, we have OA = OB = radius, angle AOB = 120 deg. Denote OH as the height of triangle. H lies on AB.
=> Applying cosine and sine theorem in right triangle AHO:
OH = OA x cos 60 = 6 x (1/2) = 3 (cm)
AH = OA x sin 60 = 6 x (sqrt3)/2 = 5.2 (cm)
=> triangle AOB area:
A = triangle AOH area x 2
= AH x OH x (1/2) x 2 = 3 x 5.2 x (1/2) x 2 = 15.6 (cm2)
=> shaded segment area = section OAB area - triangle AOB
= 37.7 - 15.6 = ~21.1 (cm2)
Hope this helps!
:)
Answer:
Area of the figure = 31.25π cm²
Perimeter of the figure = (12.5π + 10) cm
Step-by-step explanation:
Area of the given figure = Sum of area of the two semicircle + area of a quarter circle
Area of one quarter circle (CDE) = 
= 
= 6.25π
Area of one semicircle = 2 × Area of one quarter circle
= 2(6.25π)
= 12.5π
Area of the given figure = 2×12.5π + 6.25π
= 25π + 6.25π
= 31.25π cm²
Perimeter of the figure = Perimeter of two semicircles + perimeter of one quarter circle + measure of radius DE + measure of radius AB
Perimeter of one semicircle = πr
= 5π cm
Perimeter of one quarter circle = 2.5π
Perimeter of the complete figure = 10π + 2.5π + 5 + 5
= (12.5π + 10) cm
we can start a relationship together
Step-by-step explanation:
im soo
Answer:
∠1 = 90°
∠2 = 26°
Step-by-step explanation: