-Make variables
-Write equation given using variables
-Plugin the equation for L with 2w to solve for W.
-plugin W value to solve for L
Answer:
<h3>
y = 20</h3><h3 />
Step-by-step explanation:
line RPN = 180 = 4y - 10 + 90 + y
180 - 90 + 10= 5y
100 = 5y
y = 100/5
y = 20
Answer:
6 meters by 9 meters
Step-by-step explanation:
<u><em>Step 1: Formula for perimeter of rectangle</em></u>
Rectangle's perimeter = 2 (length) + 2 (width)
Rectangle's perimeter = 2 (length + width)
<u><em>Step 2: Find the length and width in terms of x</em></u>
Width = x
Length = 1.5 times width
Length = 1.5x
<u><em>Step 3: Find x</em></u>
Perimeter = 2(length + width)
30 = 2 (1.5x + x)
30/2 = 2.5x
15/2.5 = x
x = 6
<u><em>Step 4: Find the length and width</em></u>
Width = x = 6 meters
Length = 1.5x = 1.5(6) = 9 meters
Therefore, the dimensions of the room are 6 meters and 9 meters.
X/2-y/3=3/2
(6×x/2)-(6×y/3)=6×3/2
3x-2y=9______(1)
x/3+y/2=16/3
(6×x/3)+(6×y/2)=6×16/3
2x+3y=32_____(2)
(1)×3____9x-6y=27____(3)
(2)×2____4x+6y=64____(4)
(3)+(4)___13x=91
x=7
3(7)-2y=9
-2y=-12
y=6
Area: If you multiply 2 1/3 by 5 2/5, you get an answer of about: 12.6, which means the area is about: 12.6in. squared.
Perimeter: If you add 2 1/3+ 2 1/3+ 5 2/5+ 5 2/5 you get an answer of about: 15.47. So, the perimeter is about 15.47in.
Note: If you aren't allowed to use a calculator on this test, you should probably multiply the numbers yourself so you get show the work and get the answer in a fraction, which is probably what they want. If you are allowed to use calculators, all the information you need is right here.
