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maxonik [38]
2 years ago
8

Hello, can anyone help me im stuck

Mathematics
1 answer:
Ratling [72]2 years ago
6 0

Answer:

124.5

Step-by-step explanation:

We need to use two different area formulas to get our final answer.

We need the area formula for the triangle = (h*b) / 2; h = height, b = base.

We also need the area for the circle = \pi r^2. r is radius, we will replace pi with 3.14 per instructions.

To start off, let's do the circle. A = 3.14*r^2. r is given to us, r is 8.

So, just plug this into a calculator:

3.14(8^2)=200.96

This would be the area of the circle if it was full, however, we only have half of the circle, so we will divide the area in half to get our final circle area, which is 100.48 ft.

Now, for the triangle. Our height is the radius of the circle, which is 8. And our base is 6 feet. Use the formula to get the area for the triangle.

A = 8*6 / 2 = 24

The area of the triangle is 24 feet. Now, we will combine the triangle area and circle area to get our final answer.

100.48 + 24 = 124.48

Round to the nearest hundredth and you get: 124.5 ft^2

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ExtremeBDS [4]
The height of the triangular base of the pyramid is calculated through the equation,
                                        h = (cos x)(18 in)
where h is height and x is half of the angle of the triangle. Since the triangle is equilateral, the value of  x is 30°. Substituting,
                                        h = (cos 30°)(18 in)
                                        h = 15.59 in
Thus, the height of the base is approximately 15.59 inches. 
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4 years ago
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Just need help with 4. Please
konstantin123 [22]

Answer:

11 3/5*9*12 1/2=1,305

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Hope I helped.

Step-by-step explanation:

6 0
3 years ago
Please solve. 6(3 + 8) - 4/5
Gre4nikov [31]

G'Day mate! Here's the answer:

53 1/3

1. 6(3 + 6) - 4/5

2. 6 x 3 is 18, and 6 x 8 is 48

3. 18 plus 48 is 66

4. 66 - 4/5 = 266/5

5. 266/5 as mixed number is 53 1/5

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3 years ago
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What is the length of AB?
Xelga [282]

Answer:

<em>AB = 7.35 cm</em>

Step-by-step explanation:

From the attachment,

In ΔDEF,

DF = GH-(GD+FH) = 6 - (2+3) = 1 cm

DE = 2+3 = 5 cm (sum of two radius)

Applying Pythagoras theorem,

EF=\sqrt{DE^2-DF^2}=\sqrt{5^2-1^2}=\sqrt{24}=2\sqrt6

In ΔCDI,

DI = GH-(GD+IH) = 6 - (2+1.5) = 2.5 cm

CD = 2+1.5 = 3.5 cm (sum of two radius)

Applying Pythagoras theorem,

CI=\sqrt{CD^2-DI^2}=\sqrt{3.5^2-2.5^2}=\sqrt6

AB = EF + CI = 2\sqrt6+\sqrt6=3\sqrt6=7.35\ cm

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4 years ago
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Write the equation for a rational function with a hole at x = 6 and
Kisachek [45]

Answer:

x-6/x²-x-30

Step-by-step explanation:

(x-6)(x+5)

x²-x-30

when you factor out  x-6 you have a removable discontinuity and you have x+5 as your denominator and that would be the vertical asymptote since you can have a 0 as your denominator the V.A. would be x = -5.

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