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2 years ago

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8. A bag contains 2 black marbles, 3 red marbles and 4 orange marbles. Two marbles are drawn from the bag, without replacement.

Use tree diagram to find the probability that the marbles drawn are of different colours.

2 answers:

VladimirAG [237]2 years ago

8 0

I don’t know the answer

Nana76 [90]2 years ago

4 0

Answer:

there is a 50 percent chance

Step-by-step explanation:

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Answer:

the only one that is a function is B

Step-by-step explanation:

the rest of them have repeating inputs which makes them no functions

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3 years ago

The United States congress includes 2 sectors from each state ,plus members of the house of representatives. if r means the numb

astra-53 [7]

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2+-($)(*(*()($_((*_77392973673993939$9

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3 years ago

A formal, logical explanation of some events that includes descriptions of how things relate to one another is called a(n):

frosja888 [35]

Answer:

Theory

Step-by-step explanation:

The theory refers to an explanation of something. It should be understandable also it contains some logic behind that

It is a formal, logical for events that involved the descriptions that related the things to one another

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3 years ago

Can someone also help me with this one?

serg [7]

Answer:

120

Step-by-step explanation:

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3 years ago

An electronic product contains 48 integrated circuits. The probability that any integrated circuit is defective is 0.01, and the

BigorU [14]

Answer:

0.6173 = 61.73% probability that the product operates.

Step-by-step explanation:

For each integrated circuit, there are only two possible outcomes. Either they are defective, or they are not. The integrated circuits are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

An electronic product contains 48 integrated circuits.

This means that $n = 48$

The probability that any integrated circuit is defective is 0.01.

This means that $p = 0.01$

The product operates only if there are no defective integrated circuits. What is the probability that the product operates?

This is P(X = 0). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{48,0}.(0.01)^{0}.(0.99)^{48} = 0.6173$

0.6173 = 61.73% probability that the product operates.

5 0

3 years ago