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Margaret [11]
2 years ago
7

Lines I and M are cut by transversal N which statement would prove I//M picture attached.

Mathematics
1 answer:
Andreas93 [3]2 years ago
5 0

Answer:

2 one and pls brainlist

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Factorize 2y(2)+3y<br> Could u guys help me with this please.......please
tiny-mole [99]
4y + 3y = 7y
The answer is 7y. Because of the arithmetic rules, bracket should be taken first, then multiplication.
B = bracket
o = of
D = division
M = multiplication
A = addition
S = subtraction
5 0
3 years ago
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At the city museum, child admission is $5.70 and adult admission is $9.80 . On Sunday, four times as many adult tickets as child
Ket [755]
5.70c + 9.80a = 1526.60
a = 4c

5.70c + 9.80(4c) = 1526.60
5.70c + 39.20c = 1526.60
44.90c = 1526.60
c = 1526.60/44.90
c = 34 <=== child tickets sold

a = 4c
a = 4(34)
a = 136 ...adult tickets sold
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3 years ago
What is the value of sin20sin30sin40sin80.
Ilya [14]
1,-1,1,-1 is your answer
3 0
3 years ago
Which expression represents 22 more than the difference between 95 and 63
SashulF [63]

Answer:

C

Step-by-step explanation:

Difference: 95 - 63

22 more: (95 - 63) + 22

6 0
3 years ago
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Do one of the​ following, as appropriate.​ (a) Find the critical value z Subscript alpha divided by 2​, ​(b) find the critical v
aliya0001 [1]

Answer:

t=\pm 2.95

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The t distribution or Student’s t-distribution is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.  

Data given

Confidence =0.99 or 99%

\alpha=1-0.99=0.01 represent the significance level

n =16 represent the sample size

We don't know the population deviation \sigma

Solution for the problem

For this case since we don't know the population deviation and our sample size is <30 we can't use the normal distribution. We neeed to use on this case the t distribution, first we need to calculate the degrees of freedom given by:

df=n-1=16-1=15

We know that \alpha=0.01 so then \alpha/2=0.005 and we can find on the t distribution with 15 degrees of freedom a value that accumulates 0.005 of the area on the left tail. We can use the following excel code to find it:

"=T.INV(0.005;15)" and we got t_{\alpha/2}=-2.95 on this case since the distribution is symmetric we know that the other critical value is t_{\alpha/2}=2.95

8 0
3 years ago
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