Since the odd numbers are:
1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25
There are 13 odd numbers. From here you would multiply 25 times four to get 100 since there is 25 numbers. Then you would multiply 13, the number of odd numbers, by 4 as well and get 52. There is a 52% chance that a odd number will be picked.
Cos is the adjacent (side next to the angle in question) divided by the hypotenuse (sloped side)
for angle K, this is therefore 7/25
12y+3x-24 you times everything in the bracket by 3
<span>Let makes the table neater. event D= 100m, even E=800m
(Event D) (Event E)
A won the race (Event A) 30 50
B won the race (Event B) 60 25
A and B tied (Event T) 10 25</span>
B did not win the race today. What length of the race was it more likely to have been? The question is asking in what event did the chance of B did not win(lose + ties) is more likely. Then, you need to determine the chance for B did not win <span>in both race.
Chance of B </span>did not win <span>100-m= 30+10/10=40%
</span>Chance of B did not win 800-m= 50+25/10=75%
The difference would be 75%-40%=35% more likely to lose 800-m race
