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Blababa [14]
2 years ago
5

The equation of line AB is y = 5x + 1. Write an equation of a line parallel to line AB in slope-intercept form that contains poi

nt (4, 5).
a) y = 5x - 15
b) y = 5x + 15
c) y = 1/5 + 21/5
d) y = 1/5 - 29/5
Mathematics
2 answers:
Ierofanga [76]2 years ago
6 0

Answer:

your answer is d. hope this helped and pls mark brainlest

Step-by-step explanation:

Zolol [24]2 years ago
4 0

Answer:

The equation of the line y= 5x+1. Line that is parallel to the function given should have the same slope as the equation which is 5. We use the point-slope form in order to find the second equation that contains the point (4,5).

y - 5 = 5(x-4)

y = 5x - 20 +5

y≈ 5x -15

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Use the method of cylindrical shells to find the volume v generated by rotating the region bounded by the curves about the given
kondor19780726 [428]

Answer:

The volume is \frac{16\pi}{e}

Step-by-step explanation:

* Lets talk about the shell method

- The shell method is to finding the volume by decomposing

 a solid of revolution into cylindrical shells

- Consider a region in the plane that is divided into thin vertical  

 rectangle

- If each vertical rectangle is revolved about the y-axis, we

 obtain a cylindrical shell, with the top and bottom removed.  

- The resulting volume of the cylindrical shell is the surface area 

  of the cylinder times the thickness of the cylinder

- The formula for the volume will be: V=\int\limits^b_a {2\pi xf(x)} \, dx

  where 2πx · f(x) is the surface area of the cylinder shell and  dx is its

  thickness

* Lets solve the problem

- To find the volume V generated by rotating the region bounded

  by the curves y = 4e^x and y = 4e^-x about the y-axis by use

  cylindrical shells

- Consider that the height of the cylinder is y = (4e^x - 4e^-x)

- Consider that the radius of the cylinder is x

- The limits are x = 0 and x = 1

- Lets take 2π and 4 as a common factor out the integration

∴ V=\int\limits^1_0 {2\pi x(4e^{x}-4e^{-x})} \, dx

∴ V=2\pi(4)\int\limits^1_0 ({xe^{x}-xe^{-x})} \, dx

- To integrate xe^{x} and xe^{-x} we will use

  integration by parts methods \int\ {uv'=uv-\int{v}\,u' }\,

∵ u = x

∴ u' = du/dx = 1 ⇒ differentiation x with respect to x is 1

∵ v' = dv/dx = e^x

- The integration e^x is e^x ÷ differentiation of x (1)

∴ v=\int\ {e^{x}}\, dx= e^{x}

∴ \int\ {xe^{x}} \, dx=xe^{x}-\int\ e^{x}\, dx=xe^{x}-e^{x}

- Similar we will integrate xe^-x

∵ u = x

∴ u' = du/dx = 1

∵ v' = dv/dx = e^-x

- The integration e^-x is e^x ÷ differentiation of -x (-1)

∴ v=\int\ {e^{-x}} \, dx=-e^{-x}

∴ \int\ {x}e^{-x}\, dx=-xe^{-x}+\int\ {e^{-x}} \, dx=-xe^{-x}-e^{-x}

∴ V = 8\pi \int\limits^1_0 ({xe^{x}-xe^{-x})} \, dx=8\pi[xe^{x}-e^{x}+xe^{-x}+e^{-x}] from 0 to 1

- Lets substitute x = 1 minus x = 0

∴ V=8\pi[(1)(e^{1})-(e^{1})+(1)(e^{-1})+(e^{-1})-(0)(e^{0})+(e^{0})-(0)(e^{0})-(e^{0})]

∴ V=8\pi[e^{1}-e^{1}+e^{-1}+e^{-1}-0+1-0-1]=8\pi[2e^{-1}]=16\pi e^{-1}

∵ e^{-1}=\frac{1}{e}

∴ V=\frac{16\pi}{e}

3 0
4 years ago
I need 1 more credit to pass my class!
katrin [286]

Answer:

the answer is 3

Step-by-step explanation:

you piece of garbage im tryna help why u report me

3 0
3 years ago
What is AE ? <br><br><br> ___ units
sattari [20]


We can form two ratios to help us solve this:

(2x+6):10 = (x+6):8


(2x+6)         (x+6)
---------   =   --------
   10              8


Cross multiply:
8(2x+6) = 10(x+6)

Foil:
16x + 48 = 10x + 60

Move like variables to the same side:
16x - 10x = 60 - 48
6x = 12
x = 2

Line AE = 2x+6
Plug 2 for x into the equation: 2(2) + 6 = 10

Hope this helps, and May the Force Be With You!

-Jabba



6 0
3 years ago
Mary wants to paint her bedroom. Each wall takes 1/3 of a liter of paint. If she buys 2 liters ? point
sashaice [31]

2 liters of paint / 1/3 liter  per wall = 2 x 3/1 = 6/1 = 6 walls

7 0
3 years ago
If f(x) = 3x-4, and g(x) = 2f(x)-1, what is g(5)?
kvasek [131]

Answer:

g(5) = 21

Step-by-step explanation:

Substituting f(x) into g(x):

g(x) = 2(3x-4) - 1

= 6x - 8 - 1

= 6x - 9

Seeing that g(x) = 6x-9,

g(5) = 6(5) - 9

= 30 - 9

= 21

<em>Feel free to mark this as brainliest! :D</em>

6 0
3 years ago
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