All categories

2 years ago

Find the area of trapezoid JKLM. Round the answer to the nearest tenth.

Mathematics

1 answer:

maksim [4K]2 years ago

5 0

from the diagram, we can see that the height or line perpendicular to the parallel sides is 8.5.

likewise we can see that the parallel sides or "bases" are 24.3 and 9.7, so

$\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ h=8.5\\ a=24.3\\ b=9.7 \end{cases}\implies \begin{array}{llll} A=\cfrac{8.5(24.3+9.7)}{2}\\\\ A=\cfrac{8.5(34)}{2}\implies A=144.5~in^2 \end{array}$

You might be interested in

2. About 40 millions of aluminum cans can be recycled each month in the US. A quarter of these aluminum cans are used to make on

geniusboy [140]

Answer:

Step-by-step explanation:

About 40 millions of aluminum cans can be recycled each month in the US. A quarter of these aluminum cans are used to make one aluminum boat. How many aluminum boats can be made in one year in the US?

Given that:

Approximate Number of cans that can be recycled per month in the US = 40 million

Fraction of recycled cans that can be used to make an aluminum boat = 1/4

The number of aluminum boats that can be made in the US in one year :

If about 40 million cans are recycle per month :

The number of boat that can be made from each monthly recycled aluminum cans will be :

Number of monthly recycled can needed to make one boat:

1/4 * 40 million = 10 million cans

Hence, 40,000,000 / 10,000,000 = 4

4 aluminum boats can be made in one month :

Number of months in a year = 12

Number of aluminum boats that can be made in a year :

4 per month * 12 = 48 aluminum boats

5 0

2 years ago

Please help I was supposed to do this yesterday <br><br> If x=-4 and y= 9/2

tekilochka [14]

Answer:

1/6( $3x^{2}$ +4y)

Step-by-step explanation:

7 0

1 year ago

Read 2 more answers

Mr. Dixon is ordering pizzas and breadsticks for a school pizza party and has a budget of $76,

sladkih [1.3K]

10x+13y=76 is the awnser

5 0

2 years ago

When an object with a momentum of 80 kg ´ m/s collides with an object with a momentum of –100 kg ´ m/s the total momentum after

mojhsa [17]

This is a physics problem.

The law is that the momentum is preserved: total momentum before collsion = total momentum after collision

Momentum before collision = 80 kg.m/s - 100 kg.m/s = -20 kg.m/s

Then answer is b. - 20 kg.m/s

3 0

2 years ago

Consider randomly selecting a student at a large university, and let A be the event that the selected student has a Visa card an

ziro4ka [17]

Answer:

1) is not possible

2) P(A∪B) = 0.7

3) 1- P(A∪B) =0.3

4) a) C=A∩B' and P(C)= 0.3

b) P(D)= 0.4

Step-by-step explanation:

1) since the intersection of 2 events cannot be bigger than the smaller event then is not possible that P(A∩B)=0.5 since P(B)=0.4 . Thus the maximum possible value of P(A∩B) is 0.4

2) denoting A= getting Visa card , B= getting MasterCard the probability of getting one of the types of cards is given by

P(A∪B)= P(A)+P(B) - P(A∩B) = 0.6+0.4-0.3 = 0.7

P(A∪B) = 0.7

3) the probability that a student has neither type of card is 1- P(A∪B) = 1-0.7 = 0.3

4) the event C that the selected student has a visa card but not a MasterCard is given by C=A∩B' , where B' is the complement of B. Then

P(C)= P(A∩B') = P(A) - P(A∩B) = 0.6 - 0.3 = 0.3

the probability for the event D=a student has exactly one of the cards is

P(D)= P(A∩B') + P(A'∩B) = P(A∪B) - P(A∩B) = 0.7 - 0.3 = 0.4

3 0

3 years ago