Simplify the following:
(k^3 k^7)/3 - 5
Combine powers. (k^3 k^7)/3 = k^(7 + 3)/3:
k^(7 + 3)/3 - 5
7 + 3 = 10:
k^10/3 - 5
Put each term in k^10/3 - 5 over the common denominator 3: k^10/3 - 5 = k^10/3 - 15/3:
k^10/3 - 15/3
k^10/3 - 15/3 = (k^10 - 15)/3:
Answer: (k^10 - 15)/3
2/5x + 1.5y = 7x - 2y
1.5 y + 2y = 7 x - 2/5x
You can this
1.5 y + 2y = 7x - 0.4x
3.5y = 6.6x
Using proportions, it is found that the interval for the number of times Elliot must visit his parents is [14, 41].
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- The interval is found using proportions, by a rule of three.
- In each visit to his parents, Elliot flies 350 miles.
- To qualify for Gold status, he must fly at least 4900 miles. How many trips are this:
1 trip - 350 miles
x trips - 4900 miles
Applying cross multiplication:
![350x = 4900](https://tex.z-dn.net/?f=350x%20%3D%204900)
![x = \frac{4900}{350}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B4900%7D%7B350%7D)
![x = 14](https://tex.z-dn.net/?f=x%20%3D%2014)
He must visit his parents at least 14 times.
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- Also less than 14700 miles, how many trips are this?
1 trip - 350 miles
x trips - 14700 miles
![350x = 14700](https://tex.z-dn.net/?f=350x%20%3D%2014700)
![x = \frac{14700}{350}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B14700%7D%7B350%7D)
![x = 42](https://tex.z-dn.net/?f=x%20%3D%2042)
Less than 42 trips, thus at most 41 times.
The interval is [14, 41].
A similar problem is given at brainly.com/question/24112433
1/2n + 15 = 9 <== ur equation
1/2n = 9 - 15
1/2n = - 6
n = -6 * 2
n = - 12 <== ur solution
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