The solution for this problem is:It's given that the heights are normally distributed.
5 feet 7 inches = (5*12 +7) inches = (60+7) inches = 67 inches.
The z-score is (67 - 69.1)/(2.65) = -1.136. The probability is 0.127978 or 12.8%, making probability of a height over 67 inches
32x100 (add 2 zeros to 32)
3200
Answer:
12in squared
Step-by-step explanation:
Answer:
bruh finally
Step-by-step explanation:
