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zavuch27 [327]
2 years ago
8

Mars and Earth are very different because Group of answer choices Mars greenhouse effect is too strong Mars is too far from the

Sun Mars mass is too small to retain an atmosphere like Earth Mars had too many impacts from asteroids which evaporated all the water
Geography
1 answer:
ioda2 years ago
8 0

Answer: Yes the answer is true. How ever, you can add a few points like:

Explanation: If nuclear bombs were blown at the end of mars ploes, it could change its weather.(Elon Musk). It is also observed that there is higher oxygen levels in the northern parts of mars.(information from Uae mars probe). So yes you are right but there are /can be a few similarities between earth and mars.

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What landform makes up much of Western Europe was formed by sheets of ice during the ice age
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Sneak attack against the U.S. naval base in Hawaii by the empire of japan on December 7, 1941
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Our Sun emits most of its radiation at a wavelength of 550nm. If a star were 5.00 times hotter than our Sun, it would emit most
likoan [24]

Answer:

\lambda_{star} = 1.100\times 10^{-7} meter

Explanation:

By wein's law

\lambda\times T= 2.898\times 10^{-3} kelvin meter

where;

λ = wavelenght

T= Temperature (in kelvin)

2.898\times 10^{-3} mk = Wein's constant

so

\lambda\times  T(sun) = 2.898\times 10^{-3}

550\times 10^{-9}\times T (sun) = 2.898\times 10^{-3}

T (sun) = \frac{2.898\times 10^{-3}}{ 550\times 10 ^{-9}}

T (sun) = 5269.09 kelvin

from data given we have

T( star ) = 5\times T (sun)

so,

\lambda_{star}\times  T(star) = 2.898\times 10^{-3}

\lambda_{star}\times 5\times T(sun) = 2.898\times 10^{-3}kelvin meter

\lambda_{star}\times 5\times 5269.09 = 2.898\times 10^{-3}kelvin meter

\lambda_{star} = \frac{(2.898\times 10^{-3}kelvin meter)}{(5 \times 5.269 \times 10^{3}kelvin)}

\lambda_{star} = 1.100\times 10^{-7} meter

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Where are extrusive igneous rocks typically found?
krok68 [10]
Its near a dormant volcano
5 0
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Read 2 more answers
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