The molar heat of vaporization of acetone, c3h6o, is 30. 3 kj/mol at its boiling point. How many kilojoules of heat would be lib
1 answer:
The kilojoules of heat that would be liberated by the condensation of 5. 00 g of acetone is 2.612 kJ.
<h3>What is the molar heat of vaporization?</h3>
The molar heat of vaporization is the amount of energy required to convert one mole of a chemical substance from the liquid to the gaseous phase provided that the temperature and pressure are constant.
From the given parameters:
- The molar heat of vaporization = 30.3 kJ/mol
- The mass of acetone liberated = 5.00 g
- The molar mass of acetone = 58 g/mol
Therefore, the amount of heat that would be liberated by the condensation of 5.00 g of acetone is:
= 2.612 kJ
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The Angle HCA is equal to 52°. This is arrived at using the knowledge of the Total value of Angles in a Triangle and the Total Value of Angles in a Polygon.
<h3>What other principles were used to arrive at the answer?</h3>
The other principles of mathematics that were used to arrive at the above answer are:
- Total Angles on a straight line;
- Total Angles on a point; and
- Line segments.
Step 1 - Recall that we have been given Angles AHB and BAH to be 128° and 28° respectively.
We also know that:
- The sum of angles in a triangle is 180°;...................A
- The sum of angles on a straight line is 180°;.........B
- The sum of angles in a polygon is 360°; while.....C
- The total sum of angles at a point is 360°.............D
Since A...therefore:
When ∠AHB (128°) and ∠BAH are taken from 180° we have DBA = ∠28°.
By observation, we can deduce that ∠BDE, ∠CDH, ∠CEH and ∠AEH are all right-angled triangles.
Using the above, we are able to repeat this process of solving for each angle until we have ∠HCA.
To verify that our answer is correct, recall that sum of angles in a polygon is 360°
That means:
∠BDA + ∠DHE + ∠CEH + ∠HCA = 360°
That is, 90+ 128 + 90 + 52 = 360°
See attached images and;
Learn more about Angles in a Triangle at:
brainly.com/question/25215131
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