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Ratling [72]
3 years ago
7

The perimeter of the rectangle below is:

Mathematics
1 answer:
blondinia [14]3 years ago
5 0

Answer:

18x + 28 is the perimeter

Step-by-step explanation:

As perimeter is the som of all side

So    P = 6x+8 + 3x+6 + 6x+5 + 2x+2 + 3 + x+4

          = 6x+3x+6x+2x+x + 8+6+5+2+3+4

         = 18x + 28

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8. Closest option is 8.1 Just saw your choices now!

Step-by-step explanation:

This is because if you do the work, you will get: 8.12403840464..... So, rounding, you'll get 8.

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Write a division problem such that the quotient is the same as 3/8 ÷ 3/5
77julia77 [94]

Answer:

5/18 ÷ 4/9

Step-by-step explanation:

because 3/8 ÷ 3/5 equals to  5/8 and 5/18 ÷ 4/9 also equals to 5/8

8 0
3 years ago
Read 2 more answers
Solve this equation.
Anika [276]

Answer:

Answer:  b = 58/5  or 11 3/5 or 11.6 decimal

Step-by-step explanation:

Solve for b:

b - (3 + 2/5) = 8 + 1/5

Put 3 + 2/5 over the common denominator 5. 3 + 2/5 = (5×3)/5 + 2/5:

b - (5×3)/5 + 2/5 = 8 + 1/5

5×3 = 15:

b - (15/5 + 2/5) = 8 + 1/5

15/5 + 2/5 = (15 + 2)/5:

b - (15 + 2)/5 = 8 + 1/5

15 + 2 = 17:

b - 17/5 = 8 + 1/5

Put each term in b - 17/5 over the common denominator 5: b - 17/5 = (5 b)/5 - 17/5:

(5 b)/5 - 17/5 = 8 + 1/5

(5 b)/5 - 17/5 = (5 b - 17)/5:

(5 b - 17)/5 = 8 + 1/5

Put 8 + 1/5 over the common denominator 5. 8 + 1/5 = (5×8)/5 + 1/5:

(5 b - 17)/5 = (5×8)/5 + 1/5

5×8 = 40:

(5 b - 17)/5 = 40/5 + 1/5

40/5 + 1/5 = (40 + 1)/5:

(5 b - 17)/5 = (40 + 1)/5

40 + 1 = 41:

(5 b - 17)/5 = 41/5

Multiply both sides of (5 b - 17)/5 = 41/5 by 5:

(5 b - 17)/(5 1/5) = 1/5×1/(1/5) 41

1/5×1/(1/5) = 1:

5 b - 17 = 1/5×1/(1/5) 41

1/5×1/(1/5) = 1:

5 b - 17 = 41

Add 17 to both sides:

5 b + (17 - 17) = 17 + 41

17 - 17 = 0:

5 b = 41 + 17

41 + 17 = 58:

5 b = 58

Divide both sides of 5 b = 58 by 5:

(5 b)/5 = 58/5

5/5 = 1:

Answer:  b = 58/5  or 11 3/5 or 11.6 decimal


5 0
4 years ago
PLZ IF UARE BIG BRAIN AT MATH I NEED HELP PLZ :(
adell [148]

Answer:

A and B is correct

Step-by-step explanation:

8 0
3 years ago
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