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2 years ago

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The total cost of renting a car is $30. 00 for each day the car is rented plus 28 1/2 ¢ for each mile the car is driven. What is

the total cost of renting the car for 5 days and driving 350 miles?.

1 answer:

tangare [24]2 years ago

4 0

You would do 30x5=150 then you would do 350/28.5=12.28. Then you would add 150+12.28=168.28

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2 years ago

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The point (−2,4) lies on the curve in the xy-plane given by the equation f(x)g(y)=17−x−y, where f is a differentiable function o

Nikitich [7]

The value of $\frac{dy}{dx}$ is -3. $\blacksquare$

<h2>Procedure - Differentiability</h2><h3 /><h3>Chain rule and derivatives</h3><h3 />

We derive an expression for $\frac{dy}{dx}$ by means of chain rule and differentiation rule for a product of functions:

$\frac{d}{dx}[f(x)\cdot g(y)] = [f'(x)\cdot \frac{dx}{dx}]\cdot g(y) + f(x) \cdot [g'(y)\cdot \frac{dy}{dx} ]$

$\frac{d}{dx}[f(x)\cdot g(y)] = f'(x)\cdot g(y) +f(x)\cdot g'(y)\cdot \frac{dy}{dx}$ (1)

If we know that $f(x) \cdot g(y) = 17-x-y$ , $f(-2) = 3$ ,<em> </em> $f'(-2) = 4$ ,<em> </em> $g(4) = 5$ and $g'(4) = 2$ , then we have the following expression:

$-1-\frac{dy}{dx} = (4)\cdot (5) + (3)\cdot (2) \cdot \frac{dy}{dx}$

$-1-\frac{dy}{dx} = 20 + 6\cdot \frac{dy}{dx}$

$7\cdot \frac{dy}{dx} = -21$

$\frac{dy}{dx} = -3$

The value of $\frac{dy}{dx}$ is -3. $\blacksquare$

To learn more on differentiability, we kindly invite to check this verified question: brainly.com/question/24062595

<h3>Remark</h3>

The statement is incomplete and full of mistakes. Complete and corrected form is presented below:

<em>The point (-2, 4) lies on the curve in the xy-plane given by the equation </em> $f(x)\cdot g(y) = 17 - x\cdot y$ <em>, where </em> $f$ <em> is a differentiable function of </em> $x$ <em> and </em> $g$ <em> is a differentiable function of </em> $y$ <em>. Selected values of </em> $f$ <em>, </em> $f'$ <em>, </em> $g$ <em> and </em> $g'$ <em> are given below: </em> $f(-2) = 3$ <em>, </em> $f'(-2) = 4$ <em>, </em> $g(4) = 5$ <em>, </em> $g'(4) = 2$ <em>. </em>

<em />

<em>What is the value of </em> $\frac{dy}{dx}$ <em> at the point </em> $(-2, 4)$ <em>?</em>

3 0

2 years ago

ryzh [129]

Answer:

B. -3

Explanation:

Our equation is: $\frac{24x^2+25x-47}{ax-2} =-8x-3-\frac{53}{ax-2}$ . We see that both sides have a term with denominator ax - 2, so let's add $\frac{53}{ax-2}$ to both sides:

$\frac{24x^2+25x-47}{ax-2} =-8x-3-\frac{53}{ax-2}$

$\frac{24x^2+25x-47}{ax-2}+\frac{53}{ax-2} =-8x-3$

$\frac{24x^2+25x+6}{ax-2}=-8x-3$

Now multiply both sides by ax - 2:

$24x^2+25x+6=(-8x-3)(ax-2)=-8ax^2-3ax+16x+6$

$24x^2+25x+6=(-8a)x^2+(16-3a)x+6$

We essentially want to make the terms on each side match. Look at the coefficient of x² on the left side: it's 24. That means on the right side, it should be 24, as well. Then, set -8a equal to 24:

-8a = 24

a = -3

Thus, the answer is B.

4 0

3 years ago

Read 2 more answers