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TEA [102]
2 years ago
8

It cost Evan $17.70 to send 177 text messages. How many text messages did he send if he spent $19.10?​

Mathematics
1 answer:
rusak2 [61]2 years ago
6 0

Answer:

191

Step-by-step explanation:

The amount spent for a single text:  177/17,7=0,1

x×0,1=19,1

x=19,1/0,1

x=191

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1/3 x 3/4<br> Help me plss
EastWind [94]

Answer:

1/4

Step-by-step explanation:

this should be it

(hope it helps)

8 0
2 years ago
Read 2 more answers
At a museum shop, Alysa bought two books for $28.50 and some cards for $3.25 each. Her total purchase came to $44.75. How many c
PSYCHO15rus [73]

Answer:

5

Step-by-step explanation:

44.75 - 28.50 = 16.25 so 16.25 divided by 3.25 equals 5 and 5 times 3.25 equals 16.25 and 16.25 plus 28.50 equals 44.75 so she bought 5 cards.

7 0
2 years ago
A family wants to save for college tuition for their daughter. What continuous yearly interest rate r% is needed in their saving
sergey [27]

Answer:

The continuous yearly interest is  22.5% per year.

Step-by-step explanation:

Continuous yearly interest:

Continuous yearly interest is defined as the sum of the interest comes from principle and the interest comes from interest.

The formula for continuous interest yearly is

A=Pe^{rt}

where A = The final amount =$110,000

P= principle =$4,700

r= rate of interest

t= time (in year)= 14 years

\therefore 110,000= 4,700e^{r\times 14}

\Rightarrow e^{14r}= \frac{110,000}{4,700}

Taking ln both sides

\Rightarrow ln e^{14r}= ln(\frac{110,000}{4,700})

\Rightarrow {14r}= ln(\frac{1100}{47})

\Rightarrow r=\frac{ln( \frac{1100}{47})}{14}

\Rightarrow r = 0.225  (approx)

The continuous yearly interest is 0.225 = 22.5% per year.

4 0
3 years ago
Matt buys an item with a normal price of $25 and uses a 10% off cupon. How much does he save by using the coupon?
Anika [276]
By using this coupon he will save $2.50. You have to multiply 25 by 0.10.
7 0
3 years ago
Read 2 more answers
Is the answer a, b, c, or d.
ale4655 [162]
The correct answer is d.

We have the following system of linear equations:

(I) 4x+7y=-14
(II) 8x+5y=8

Let's use the elimination method, then let's multiply the equation (1) \times(-2) and subtracting (I) and (II):

(I) -2(4x+7y)=-2(-14)
∴ -8x-14y=28

(I) -8x-14y=28
(II) 8x+5y=8
____________________
(III)  -9y=36

∴  y=-4

We can find the value of x by substituting y either in (I) or (II). Thus, from (I):

4x+7(-4)=-14
∴ 4x-28=-14
∴ 4x=14
∴ x=\frac{14}{4}
∴ \boxed{x=\frac{7}{2}}

Let's substitute the values of x and y into (I) and (2)

(I) 4(\frac{7}{2})+7(-4)=14-28=-14
(II) 8(\frac{7}{2})+5(-4)=28-20=8

Finally the answer is:

\boxed{x=\frac{7}{2} \rightarrow x= 3 \frac{1}{2}}

4 0
3 years ago
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