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vovikov84 [41]
3 years ago
12

Find the surface area of the prism.

Mathematics
2 answers:
8_murik_8 [283]3 years ago
6 0

Answer:

148^2

Step-by-step explanation:

2(lb+bh+lh) = 2(4*5+5*6+4*6)=148 in^2

hoa [83]3 years ago
5 0

Check the picture below.

as you can see, we have 6 rectangles, so let's get the area of each and sum them up and that's the area of the prism.

\stackrel{\textit{\large Areas}}{\stackrel{\textit{left and right}}{2(6\cdot 5)}+\stackrel{\textit{front and back}}{2(4\cdot 6)}+\stackrel{\textit{top and bottom}}{2(4\cdot 5)}}\implies 60+48+40\implies 148

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I need help trying to figure this out I think I have and answer but I want to make sure.
yKpoI14uk [10]

Answer:

34

Step-by-step explanation:

The mean is calculated as

mean = \frac{frequency(midpoint)}{frequency}

let x be the missing frequency, then

Total frequency × midpoint

= (16 × 2) + 7x + (20 × 12) + (10 × 17) = 32 + 7x + 240 + 170 = 442 + 7x

Total frequency = 16 + x + 20 + 10 = 46 + x, thus

\frac{242+7x}{46+x} = 8.5 ( cross- multiply )

442 + 7x = 8.5(46 + x)

442 + 7x = 391 + 8.5x ( subtract 8.5x from both sides )

442 - 1.5x = 391 ( subtract 442 from both sides )

- 1.5x = - 51 ( divide both sides by - 1.5 )

x = 34

The missing frequency is 34

3 0
3 years ago
I.5y=2x-5<br> II.5y=4+3x<br> III.5y-3x=-1
Ratling [72]

Answer:

Step-by-step explanation:

the vale of x differs in each situation are we talking AB value

6 0
3 years ago
A recommendation for wheelchair ramps is that the rise-to-run ratio be no greater than 1:12. This ensures that the ramps are nav
patriot [66]

Answer:

a. 12 feet b. 12 feet 0.5 inches c. 8.33 %

Step-by-step explanation:

a. How far out horizontally on the ground will it protrude from the building?

Since the rise to run ratio is 1:12 and the building is 12 inches off the ground, let x be the horizontal distance the ramp protrudes.

So, by ratios rise/run = 1/12 = 12/x

1/12 = 12/x

x = 12 × 12

x = 144 inches

Since 12 inches = 1 foot, 144 inches = 144 × 1 inch = 144 × 1 foot/12 inches = 12 feet

b. How long should the ramp be?

The length of the ramp, L is gotten from Pythagoras' theorem since the ramp is a right-angled triangle with sides 12 inches and 144 inches respectively.

So, L = √(12² + 144²)

= √[12² + (12² × 12²)]

= 12√(1 + 144)

= 12√145

= 12 × 12.042

= 144.5 inches

Since 12 inches = 1 foot, 144.5 inches = 144 × 1 inch + 0.5 inches = 144 × 1 foot/12 inches + 0.5 inches = 12 feet 0.5 inches

c. What percent grade is the ramp?

The percentage grade of the ramp = rise/run × 100 %

= 12 inches/144 inches × 100 %

= 1/12 × 100 %

= 0.0833 × 100 %

= 8.33 %

6 0
3 years ago
PLS HELP!! this is due today pls help me thank u so much.
riadik2000 [5.3K]

Answer:

23.3

Step-by-step explanation:

Use phyth. Thm.

a^2 + b^2 = c^2

A and B are the side lengths, and C is the hypotenuse. The hypotenuse is across the right angle.

Since you only have one side length and the hypotenuse this what your equation will look like:

30^2 + x^2 = 38^2

900 + x^ = 1444

544 = x^2

x = roughly 23.3

8 0
3 years ago
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Malik bought chargers that are shaped like regular octagons. If the chargers have the dimensions shown below, what is the area o
vlada-n [284]
What are the dimensions?


7 0
3 years ago
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