X = 40, Y = 15
40(2) + 15(2) = 80 + 30 = 110 :)
Answer:
C x=6
Step-by-step explanation:
sqrt(x+3) = x-3
Square each side
(sqrt(x+3))^2 = (x-3)^2
x+3 = (x-3)^2
x+3 = (x-3)(x-3)
FOIL
x+3 = x^2 -3x-3x+9
Combine like terms
x+3 = x^2 -6x+9
Subtract x from each side
x-x+3 = x^2 -6x-x +9
3 = x^2 -7x +9
Subtract 3 from each side
3-3 = x^2 -7x +9-3
0 = x^2 -7x+6
Factor
0 = (x-6)(x-1)
Using the zero product property
x-6=0 x-1 =0
x=6 x=1
Since we squared we need to check for extraneous solutions
x=1
sqrt(1+3) = 1-3
sqrt(4) = -2
2=-2
False
Extraneous
x=6
sqrt(6+3) = 6-3
sqrt(9) = 3
3=3
True solutions
Sine the roots x=1 and x=0 have a multiplicity of 2, we know p(x)= (x-1)^2 (x)^2 (x-a). Since we also know x=-3 is a root, we have p(x)= (x-1)^2 x^2 (x+3)
The Law of Cosine states
cos
so plugging in the numbers gives us
cos
We now have cosJ so plug that into your calculator and find arccos (arccos(cos(J)) = J)
arccos
rounding your answer will give you 34°
<span>PQ = 7.2
Thank you for describing the triangle. If you examine the figure you described, you'll realize that triangles MNO and QPO are similar triangles, with triangle QPO being half the size of triangle MNO. You can see this because both triangles have QOP as one of their angles and line segment PO is half the length of line segment NO as evidenced by the double tick marks on each side of the bisector P. Additionally, you can see that line segment QO is half the length of line segment MO as evidenced by point Q being the bisector of MO with the single tick mark on both sides of the bisector. So the length of PQ is half of the length of MN. And 14.4/2 = 7.2</span>