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3 years ago

How can you solve for x?

Mathematics

2 answers:

olchik [2.2K]3 years ago

7 0

Answer:

Step-by-step explanation:

<h3>total answer is 55</h3><h3>but hold same angle form both because the line are parallel and simple straigths lines of angle</h3>

<h2>PA BRAINLEST NALANG</h2><h2>#HOPE ITS HELPS </h2><h3>#CARE ON LEARNING</h3>

Ierofanga [76]3 years ago

3 0

Answer:

x = 55°

Step-by-step explanation:

From given figure we have

Two lines parallel

As we know simple straight line maintain an angle of 180°

Third line bisecting the two parallel lines at different position

But hold same same angle form both because lines are parallel.

To find angle = 180 - 125 = 55

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P(-,3) , Q(7,-3) and R (4,1) are three points. show that PQ=2QR using distance formula. (please show the steps too :)

solong [7]

Answer:

PQ is 10.

QR is 5.

Hence, PQ=2QR

Step-by-step explanation:

We have the three points P(-1, 3); Q(7, -3); and R(4, 1).

And we want to show that PQ=2QR.

In other words, we want to show that PQ/QR=2.

So, let's find PQ and QR. We will need to use the distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

To find PQ:

P is (-1, 3) and Q is (7, -3).

So, we will let P(-1, 3) be (x₁, y₁) and Q(7, -3) be (x₂, y₂).

Substitute the values into the distance formula. This yields:

$d=\sqrt{(7-(-1))^2+(-3-3)^2$

Evaluate:

$d=\sqrt{(8)^2+(-6)^2$

Evaluate:

$d=\sqrt{64+36}=\sqrt{100}=10$

So, the distance of PQ is 10.

And to find QR:

Q is (7, -3) and R is (4, 1).

Again, we will let Q(7, -3) be (x₁, y₁) and R(4, 1) be (x₂, y₂).

Substitute appropriately. So:

$d=\sqrt{(4-7)^2+(1-(-3))^2$

Evaluate:

$d=\sqrt{(-3)^2+(4)^2$

Evaluate:

$d=\sqrt{9+16}=\sqrt{25}=5$

So, the distance of QR is 5.

Therefore, it follows that:

$\displaystyle PQ=2QR\Rightarrow \frac{PQ}{QR}=2\Rightarrow\frac{10}{5}\stackrel{\checmark}{=}2$

And we have shown that PQ=2QR.

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3 years ago