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Alex Ar [27]
3 years ago
11

Find the second fourth and eleventh terms of the sequence described by each rule A(n)=9+(n-1)(8)

Mathematics
1 answer:
agasfer [191]3 years ago
4 0
A(n) = 9 + (n - 1) * 8

2nd term....n = 2
A2 = 9 + (2 - 1)*8
A2 = 9 + 1 * 8
A2 = 9 + 8
A2 = 17 <==

4th term...n = 4
A4 = 9 + (4 - 1) * 8
A4 = 9 + 3 * 8
A4 = 9 + 24
A4 = 33 <==

11th term...n = 11
A11 = 9 + (11 - 1) * 8
A11 = 9 + 10 * 8
A11 = 9 + 80
A11 = 89 <==
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Provide an appropriate response.
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8 0
3 years ago
Simplify [7+2(5 - 9)2]/[(4+1)2 - 3(22)
svet-max [94.6K]

Answer:

9/56 is your answer.

Step-by-step explanation:

[7+2(5 - 9)2]/[(4+1)2 - 3(22)=

[7+2(-4)2]/[(5)2-66]=

[7+2(-8)]/[10-66]=

(7+-16)/(-56)=

-9/-56=

9/56 is your answer.

4 0
4 years ago
Read 2 more answers
Help me to solve this questions please.
Yuki888 [10]
I think it is 76 ....... I may be wrong
8 0
3 years ago
Break apart ones to make a ten<br><br> 62 + 9 =
dsp73

Answer:

71

Step-by-step explanation:

I know this because 62 and 9 equal 71

7 0
4 years ago
Please oh please help me I don’t want too fail!
SCORPION-xisa [38]

Answer:

D

Step-by-step explanation:

The best bet would be D because if its going counterclockwise 360 degrees then it would make a full rotation going back to the same position although I would work out the problem to the best of your ability just to make sure because I'm not entirely sure about my answer.

7 0
3 years ago
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