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Alex Ar [27]
3 years ago
11

Find the second fourth and eleventh terms of the sequence described by each rule A(n)=9+(n-1)(8)

Mathematics
1 answer:
agasfer [191]3 years ago
4 0
A(n) = 9 + (n - 1) * 8

2nd term....n = 2
A2 = 9 + (2 - 1)*8
A2 = 9 + 1 * 8
A2 = 9 + 8
A2 = 17 <==

4th term...n = 4
A4 = 9 + (4 - 1) * 8
A4 = 9 + 3 * 8
A4 = 9 + 24
A4 = 33 <==

11th term...n = 11
A11 = 9 + (11 - 1) * 8
A11 = 9 + 10 * 8
A11 = 9 + 80
A11 = 89 <==
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