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2 years ago

Someone tell me the answer

Mathematics

1 answer:

Zarrin [17]2 years ago

3 0

Answer: 6:1

Step-by-step explanation: you’re welcome

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Solve x^2 + 6x = 24.

Sunny_sXe [5.5K]

Hello DestinyKiara99 o/
We can solve this equation using the quadratic formula
Check it out...

x² + 6x - 24 = 0

Δ = 6² - 4.1.(-24)
Δ = 36 + 96
Δ = 132

x = -6 +/- √132 x' = -3 + √33
<span> -------------- /
2 \
x'' = - 3 - </span>√33
The correct answer is the letter D
I hope this help =)

8 0

2 years ago

State the property.<br>4(2+3)=(2+3)4

Komok [63]

Hmm, it looks like it could be commutative property of multiplication.

The order of the expression is different.

4(2+3)=

4(5)=20

(2+3)4=

(5)4= 20

8 0

2 years ago

Find the partial fraction decomposition of the rational expression with prime quadratic factors in the denominator

SpyIntel [72]

$\dfrac{5x^4-7x^3-12x^2+6x+21}{(x-3)(x^2-2)^2}=\dfrac{a_1}{x-3}+\dfrac{a_2x+a_3}{x^2-2}+\dfrac{a_4x+a_5}{(x^2-2)^2}$
$\implies 5x^4-7x^3-12x^2+6x+21=a_1(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(a_4x+a_5)(x-3)$

When $x=3$ , you're left with

$147=49a_1\implies a_1=\dfrac{147}{49}=3$

When $x=\sqrt2$ or $x=-\sqrt2$ , you're left with

$\begin{cases}17-8\sqrt2=(\sqrt2a_4+a_5)(\sqrt2-3)&\text{for }x=\sqrt2\\17+8\sqrt2=(-\sqrt2a_4+a_5)(-\sqrt2-3)\end{cases}\implies\begin{cases}-5+\sqrt2=\sqrt2a_4+a_5\\-5-\sqrt2=-\sqrt2a_4+a_5\end{cases}$

Adding the two equations together gives $-10=2a_5$ , or $a_5=-5$ . Subtracting them gives $2\sqrt2=2\sqrt2a_4$ , $a_4=1$ .

Now, you have

$5x^4-7x^3-12x^2+6x+21=3(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(x-5)(x-3)$
$5x^4-7x^3-12x^2+6x+21=3x^4-11x^2-8x+27+(a_2x+a_3)(x-3)(x^2-2)$
$2x^4-7x^3-x^2+14x-6=(a_2x+a_3)(x-3)(x^2-2)$

By just examining the leading and lagging (first and last) terms that would be obtained by expanding the right side, and matching these with the terms on the left side, you would see that $a_2x^4=2x^4$ and $a_3(-3)(-2)=6a_3=-6$ . These alone tell you that you must have $a_2=2$ and $a_3=-1$ .

So the partial fraction decomposition is

$\dfrac3{x-3}+\dfrac{2x-1}{x^2-2}+\dfrac{x-5}{(x^2-2)^2}$

7 0

2 years ago

What is x in the equation in -4(3x+7)= 4

Nana76 [90]

Answer:

-12x-28=4

-12x=32

x=-16/3

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Plz help last one ty!!!!!!!

azamat

My apologies on answering late...

Same situation as the previous problem, but this time, all you need to do is state the degree of the angle instead of just providing the angle itself.

ΔABC ≅ ΔDEF

Now, we can see that ∠C ≅ ∠F. Using this information, we can find ∠C on the first triangle ( which is $75$ ° ).

Since ∠C ≅ ∠F,

m∠F is $75$ °.

Hope I caught your question in time!

Have a good one! If you need anymore help, let me know.

4 0

3 years ago