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muminat
2 years ago
9

The sides of One World Trade Center in New York City form

Mathematics
1 answer:
tester [92]2 years ago
7 0

The value of ∠BAC in the isosceles triangle is 9.7°

<h3>Cosine rule</h3>

Cosine rule is used to show the relationship between the sides and angles of a triangle. It is given by:

a² = b² + c² - 2bc*cos(A)

where a, b, c are the sides of the triangle and A, B, C are the angles opposite the sides.

AB = AC = 1185 (isosceles), BC = 200, let ∠BAC = x°, hence:

200² = 1185² + 1185² - 2(1185)(1185)cos(x)

2(1185)(1185)cos(x) = 2808450

cos(x) = 0.9857

x = 9.7°

The value of ∠BAC in the isosceles triangle is 9.7°

Find out more on Cosine rule at: brainly.com/question/7872492

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There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl
Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0
3 years ago
30 points + brainliest for correct answer! If a triangle has sides X, 4.0, and 8.0, what is the range of possible sizes for side
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Two sides of a triangle have length 6 and 8. Which of the following are possible areas of the triangle?

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Correct answer will get brainliest
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Answer:

I believe its B, But I am unsure since I haven't done geometry in a couple years.

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Help explain!!!! please
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