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zloy xaker [14]
2 years ago
7

I need help I’m so stuck on this

Mathematics
1 answer:
frutty [35]2 years ago
8 0

Answer:

x = 40

Step-by-step explanation:

x/4 = 10

x/4 x 4 = 10 x 4

x = 40

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Arrange the following polynomial into descending order for x, then interpret the degree of the 3rd term. 2xy4 + 2x2y − 3y2 + 10x
Darina [25.2K]
The arrangement should be based on the decreasing degree of the terms which may be determined by the variable x as it should come first in alphabetical order. The polynomial is then,
                         10x³ + 2x²y + 2xy^4 - 3y²
The degree is equal to the sum of the exponents. Thus, the answer is 5 and it is letter D. 
8 0
3 years ago
Read 2 more answers
Find the vertical component given that R = 42 lb. and = 80.<br><br> 41.36<br> 7.29<br> 59.45
valentina_108 [34]

Answer:

a

Step-by-step explanation:

3 0
2 years ago
What is the slant height of a square pyramid that has a surface area of 319 square feet and a side length of 11 feet?
Dafna1 [17]

Step-by-step explanation:

Surface area of a square pyramid is the area of the square base plus the area of the four triangles made from the base and the slant height.

SA = s² + 4(sh/2)

which reduces to:

SA = s² + 2sh

You are told that s = 11 and SA = 319. You can now solve for h:

319 = 11² + 2(11)h

319 = 121 + 22h

198 = 22h

h = 9 ft (answer C)

I hope it's helpful!!

7 0
3 years ago
Read 2 more answers
1.) Find the length of the arc of the graph x^4 = y^6 from x = 1 to x = 8.
xxTIMURxx [149]

First, rewrite the equation so that <em>y</em> is a function of <em>x</em> :

x^4 = y^6 \implies \left(x^4\right)^{1/6} = \left(y^6\right)^{1/6} \implies x^{4/6} = y^{6/6} \implies y = x^{2/3}

(If you were to plot the actual curve, you would have both y=x^{2/3} and y=-x^{2/3}, but one curve is a reflection of the other, so the arc length for 1 ≤ <em>x</em> ≤ 8 would be the same on both curves. It doesn't matter which "half-curve" you choose to work with.)

The arc length is then given by the definite integral,

\displaystyle \int_1^8 \sqrt{1 + \left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx

We have

y = x^{2/3} \implies \dfrac{\mathrm dy}{\mathrm dx} = \dfrac23x^{-1/3} \implies \left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2 = \dfrac49x^{-2/3}

Then in the integral,

\displaystyle \int_1^8 \sqrt{1 + \frac49x^{-2/3}}\,\mathrm dx = \int_1^8 \sqrt{\frac49x^{-2/3}}\sqrt{\frac94x^{2/3}+1}\,\mathrm dx = \int_1^8 \frac23x^{-1/3} \sqrt{\frac94x^{2/3}+1}\,\mathrm dx

Substitute

u = \dfrac94x^{2/3}+1 \text{ and } \mathrm du = \dfrac{18}{12}x^{-1/3}\,\mathrm dx = \dfrac32x^{-1/3}\,\mathrm dx

This transforms the integral to

\displaystyle \frac49 \int_{13/4}^{10} \sqrt{u}\,\mathrm du

and computing it is trivial:

\displaystyle \frac49 \int_{13/4}^{10} u^{1/2} \,\mathrm du = \frac49\cdot\frac23 u^{3/2}\bigg|_{13/4}^{10} = \frac8{27} \left(10^{3/2} - \left(\frac{13}4\right)^{3/2}\right)

We can simplify this further to

\displaystyle \frac8{27} \left(10\sqrt{10} - \frac{13\sqrt{13}}8\right) = \boxed{\frac{80\sqrt{10}-13\sqrt{13}}{27}}

7 0
3 years ago
A man divided $9,000 among his wife, son, and daughter. The wife received twice as much as the daughter, and the son received $1
monitta

Answer:

Q1:

Share of the daughter (x):

2x + x + x + $1,000 = $9,000

4x = $8,000

x = $2,000

Share of the wife:

= 2($2,000)

=  $4,000

Share of the son:

= $2,000 + $1,000

= $3,000

Answer: wife, $4,000; son, $3,000; daughter, $2,000

Q2:

= 1/2x + $1,000

Answer: 1/2x + $1,000: expression for share of the son

Proof (the wife shares $4,000):

Share of wife (x):

x + 1/2x + 1/2x + $1,000 = $9,000

2x = $8,000

x = $4,000

Step-by-step explanation:

hope it helps!

6 0
3 years ago
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