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erastovalidia [21]

3 years ago

8

Solve it (tanθ−cotθ)(tan2θ+tanθ⋅cotθ+cotθ)

1 answer:

olya-2409 [2.1K]3 years ago

5 0

Answer:

sin(θ)^2 + tan2θ + sin(θ)^2 + cosθsinθ - cos(θ)^2. sinθ.tan2θ - cos(θ)^2 . sinθ - cos(θ)^2 / cosθsinθ

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How can u find the volume of a rectangular prism using a model

enyata [817]

You can find the volume by using a model by counting how many cubes are in the front and multiply it by the width.

Kinda like length x width x height.

7 0

3 years ago

Read 2 more answers

Decrease £280 by 73%

bekas [8.4K]

280 x (1-0.73)
=280 x 0.37
= £103.60

£280 decreased by 73% is <span>£280 multiplied by 37%.

</span>If this answer has helped you, please make sure to leave a Thank You.

4 0

3 years ago

Find the ordered triple of these equations.<br> X + y + z = 12<br> y = 1<br> X - Y - Z = 0

patriot [66]

Answer:

the ordered triple of these equations will be:

(x, y, z) = (6, 1, 5)

Step-by-step explanation:

Given the equations

$x + y + z = 12$

$y=1$

$x - y - z = 0$

As

$y=1$

We can get the value of x by adding the first and third equation

so

$x + y + z = 12$

$x-y-z=0$

so the equations become

$x+x+y-y+z-z=12+0$

$2x = 12$

$x = 6$

Putting x = 6 and y=1 in the first equation $x+y+z=12$

$6 + 1+ z = 12$

$7 + z = 12\\z = 12 -7$

$z = 5$

Therefore, the ordered triple of these equations will be:

(x, y, z) = (6, 1, 5)

6 0

3 years ago

The formula for the perimeter of a rectangle is P=2(l+w). Solve for l.

Readme [11.4K]

Answer:

l = $\frac{P-2w}{2}$

Step-by-step explanation:

Given

P = 2(l + w) ← distribute right side

P = 2l + 2w ( subtract 2w from both sides )

P - 2w = 2l ( isolate l by dividing both sides by 2 )

$\frac{P-2w}{2}$ = l

7 0

3 years ago

Read 2 more answers

A tank holds 50 gal of water, which drains from a leak at the bottom, causing the tank to empty in 20 min. The tank drains faste

kirza4 [7]

Answer:

(a) V(0) = 50 gal, V(20) = 0 gal

(b)At t= 0 the tank is full.

At t=0 the tank is empty

(c)

Time volume

0 50 gal

5 37.5 gal

10 25 gal

15 12.5 gal

20 0 gal

(d)

Net change of volume = 50 gal

Step-by-step explanation:

Given that the capacity of the tank is 50 gal.

Torricelli's Law gives the volume of water remaining in the tank after t minutes as

$V(t)=50(1-\frac{t}{20})^2$

(a)

To find V(0), we put t = 0 in the above equation

$V(0)=50(1-\frac{0}{20})^2$

$=50(1-0)^2$

= 50 gal

To find V(20), we put t =2 0 in the above equation

$V(20)=50(1-\frac{20}{20})^2$

$=50(1-1)^2$

= 0 gal

(b)

At t= 0 the tank is full.

At t=0 the tank is empty.

(c)

Time V(t)

0 $50(1-\frac{0}{20})^2=50 \ gal$

5 $50(1-\frac{5}{20})^2=37.5 \ gal$

10 $50(1-\frac{10}{20})^2=25 \ gal$

15 $50(1-\frac{15}{20})^2=12.5 \ gal$

20 $50(1-\frac{20}{20})^2=0$

(d)

Net change of volume = V(0) -V(20)

=(50-0) gal

= 50 gal

3 0

3 years ago