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erastovalidia [21]
3 years ago
8

Solve it (tanθ−cotθ)(tan2θ+tanθ⋅cotθ+cotθ) ​

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
5 0

Answer:

sin(θ)^2 + tan2θ + sin(θ)^2 + cosθsinθ - cos(θ)^2. sinθ.tan2θ - cos(θ)^2 . sinθ - cos(θ)^2 / cosθsinθ

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