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alexgriva [62]
2 years ago
14

Can you please help me I will give you Brainliiest..

Mathematics
1 answer:
Solnce55 [7]2 years ago
7 0

Answer:

:/

Step-by-step explanation:

necesito acabar la creación de cuenta

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Please answer and explain the link below
Leviafan [203]

Answer:

See explanation.

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Functions
  • Function Notation

<u>Calculus</u>

Limits

  • Right-Side Limit:                                                                                             \displaystyle  \lim_{x \to c^+} f(x)
  • Left-Side Limit:                                                                                               \displaystyle  \lim_{x \to c^-} f(x)

Limit Rule [Variable Direct Substitution]:                                                             \displaystyle \lim_{x \to c} x = c

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = \left \{ {{\sqrt{x + 1}, \ x < 3} \atop {5 - x, \ x \geq 3}} \right.

<u>Step 2: Find Right Limit</u>

  1. Substitute in variables [Right-Side Limit]:                                                      \displaystyle  \lim_{x \to 3^+} 5 - x
  2. Evaluate limit [Limit Rule - Variable Direct Substitution]:                           \displaystyle  \lim_{x \to 3^+} 5 - x = 5 - 3
  3. Subtract:                                                                                                         \displaystyle  \lim_{x \to 3^+} 5 - x = 2

∴ the right-side limit equals 2.

<u>Step 3: Find Left Limit</u>

  1. Substitute in variables [Left-Side Limit]:                                                       \displaystyle  \lim_{x \to 3^-} \sqrt{x + 1}
  2. Evaluate limit [Limit Rule - Variable Direct Substitution]:                           \displaystyle  \lim_{x \to 3^-} \sqrt{x + 1} = \sqrt{3 + 1}
  3. [√Radical] Add:                                                                                             \displaystyle  \lim_{x \to 3^-} \sqrt{x + 1} = \sqrt{4}
  4. [√Radical] Evaluate:                                                                                       \displaystyle  \lim_{x \to 3^-} \sqrt{x + 1} = 2

∴ the left-side limit equals 2.

<u>Step 4: Find Limit</u>

<em>The right and left-side limits are equal.</em>

∴  \displaystyle  \lim_{x \to 3} f(x) = 2

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

Book: College Calculus 10e

4 0
3 years ago
Item 10 Question 1 Your school district cancels school when more than 2.5 inches of snow accumulate on the ground each hour. Sno
Gekata [30.6K]

Answer:

Step-by-step explanation:

13

4 0
3 years ago
What is the reduced fraction form of 0.2
maw [93]

Answer: 0.2 reduced as a fraction 1/5

8 0
3 years ago
Part ?? of i need these
masha68 [24]
The answer is
R = 74
Q = 32
:)
4 0
3 years ago
Read 2 more answers
How many solutions does the system have? <br> y=−2x+2<br> y=x^2−3x
s2008m [1.1K]
Y=-2x+2 and y=x^2-3x.

If there are solutions the x and y values are equal so we can say y=y:

x^2-3x=-2x+2  add 2x to both sides

x^2-x=2  subtract 2 from both sides

x^2-x-2=0  now factor...

x^2+x-2x-2=0

x(x+1)-2(x+1)=0

(x-2)(x+1)=0

So there are two solutions, when x=-1 and 2

Using y=-2x+2 we can find the corresponding y values for the solutions...

y(-1)=-2(-1)+2=2+2=4, y(2)=-2(2)+2=-4+2=-2 so the two solutions are the points:

(-1,4) and (2,-2)
3 0
4 years ago
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