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OLEGan [10]
2 years ago
11

50 POINTS

Mathematics
1 answer:
ludmilkaskok [199]2 years ago
6 0
The area of the composite figure can be calculate

120 pi x 5.1 1922.6547
1922.6547 divided by 7.4 =259.8182
259.8182 + 3.2 = 263.0182
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In a laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5 % per hour find the bacteria at
Daniel [21]

9514 1404 393

Answer:

  5187

Step-by-step explanation:

At the end of 1 hour, the count is 2.5% greater than at the beginning.

  5060 + 2.5% × 5060 = 5060 +126.5 = 5186.5

The count at the end of the hour was about 5187.

4 0
2 years ago
Hello pls join this zoom number: 950-7126-2039
Gnom [1K]

Answer:ok I’ll join

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Suppose that five ones and four zeros are arranged around a circle. Between any two equal bits you insert a 0 and between any tw
PolarNik [594]

Answer:

Using <u>backward reasoning</u> we want to show that <em>"We can never get nine 0's"</em>.

Step-by-step explanation:

Basically in order to create nine 0's, the previous step had to have all 0's or all 1's. There is no other way possible, because between any two equal bits you insert a 0.

If we consider two cases for the second-to-last step:

<u>There were 9 </u><u>0's</u><u>:</u>

We obtain nine 0's if all bits in the previous step were the same, thus all bit were 0's or all bits were 1's. If the previous step contained all 0's, then we have the same case as the current iteration step. Since initially the circle did not contain only 0's, the circle had to contain something else than only 0's at some point and thus there exists a point where the circle contained only 1's.

<u>There were 9 </u><u>1's</u><u>:</u>

A circle contains only 1's, if every pair of the consecutive nine digits is different. However this is impossible, because there are five 1's and four 0's (we have an odd number of bits!), thus if the 1's and 0's alternate, then we obtain that 1's that will be next to each other (which would result in a 1 in the next step). Thus, we obtained a contradiction and thus assumption that the circle contains nine 0's after iteratins the procedure is false. This then means that you can never get nine 0's.

To summarize, in order to create nine 0's, the previous step had to have all 0's or al 1's. As we didn't start the arrange with all 0's, the only way is having all 1's, but having all 1's will not be possible in our case since we have an odd number of bits.

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5 0
3 years ago
In a scale drawing of a garden, a distance of 35 feet is represented by a line segment 4 inches long. on the same drawing, what
nalin [4]

Answer:

122.5\ ft

Step-by-step explanation:

we know that

Using proportion

\frac{35}{4}\frac{ft}{in}=\frac{x}{14}\frac{ft}{in}\\ \\x=35*14/4\\ \\x=122.5\ ft

7 0
3 years ago
Traveling solve 64 less than y is no less than negative 128 give your answers in interval notation
exis [7]

64 less than y = y-64

no less = greater or equal than

negative 128 = -128

y-64 ≥ -128

Add 64 to both sides of the inequality:

y-64+64 ≥ -128+64

y ≥ -64

interval :

[-64,∞)

7 0
1 year ago
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