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2 years ago

3. Which equation can not be derived from the equation given below?

Mathematics

1 answer:

daser333 [38]2 years ago

7 0

Answer:

Option A is the correct answer

A.x=2a(b-y)

Step-by-step explanation:

Reason: 2a is not a coefficient of y.

Hope it helps you in your learning process.

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At 2:00 pm there are 350 freshmen and 200 sophomores at a school carnival. After 2:00 pm 20 freshman leave every hour and 35 sop

dmitriy555 [2]

Answer:

160:340

Step-by-step explanation:

The hours between 2:00pm and 4:00pm is 2 hours. If originally 350 freshman and 200 sophomores are at the carnival, and 20 freshman leave every hour, we can determine how many freshman left in 2 hours:

$=20\cdot{2}=40$

and if 35 sophomores arrive every half our, we know that for every two hours there is 4 half hours, therefore:

$=35\cdot{4}=140$

The amount of freshman at 4:00pm:

$200-40=160$

and the amount of sophomores:

$200+140=340$

the ratio is 160:340

5 0

3 years ago

Read 2 more answers

Find the area of the polygon. 32 m 20 m 16 m 40 m he area of the polygon is square meters.

jenyasd209 [6]

Answer:

Step-by-step explanation:

4 0

3 years ago

At 7pm last night ,the temperature was 10 degrees Fahrenheit. At 7am the next morning the temperature was negative 2. By how muc

stepladder [879]

The tempature decreased by 12, because 10-12= -2

6 0

3 years ago

Read 2 more answers

1. In an auditorium, there are 21 seats in the first row and 26 seats in the second row. The number of seats in a row continues

kondor19780726 [428]

1. Let $s_n$ be the number of seats in the $n$ -th row. The number seats in the $n$ -th row relative to the number of seats in the $(n-1)$ -th row is given by the recursive rule

$s_n=s_{n-1}+5$

Since $s_1=21$ , we have

$s_2=s_1+5$
$s_3=s_2+5=s_1+2\cdot5$
$s_4=s_3+5=s_1+3\cdot5$
$\cdots$
$s_n=s_{n-1}+5=\cdots=s_1+(n-1)\cdot5$

So the explicit rule for the sequence $s_n$ is

$s_n=21+5(n-1)\implies s_n=5n+16$

In the 15th row, the number of seats is

$s_{15}=5(15)+16=91$

2. Let $p_n$ be the amount of profit in the $n$ -th year. If the profits increase by 6% each year, we would have

$p_2=p_1+0.06p_1=1.06p_1$
$p_3=1.06p_2=1.06^2p_1$
$p_4=1.06p_3=1.06^3p_1$
$\cdots$
$p_n=1.06p_{n-1}=\cdots=1.06^{n-1}p_1$

with $p_1=40,000$ .

The second part of the question is somewhat vague - are we supposed to find the profits in the 20th year alone? the total profits in the first 20 years? I'll assume the first case, in which we would have a profit of

$p_{20}=1.06^{19}\cdot40,000\approx121,024$

3. Now let $p_n$ denote the number of pushups done in the $n$ -th week. Since $3\cdot4=12$ , $12\cdot4=48$ , and $48\cdot4=192$ , it looks like we can expect the number of pushups to quadruple per week. So,

$p_n=4p_{n-1}$

starting with $p_1=3$ .

We can apply the same reason as in (2) to find the explicit rule for the sequence, which you'd find to be

$p_n=4^{n-1}p_1\implies p_n=4^{n-1}\cdot3$

6 0

3 years ago

Select the correct product.<br><br> (y + z)3

Gre4nikov [31]

Answer:

3y + 3z

Step-by-step explanation:

(y + z)3

As the parenthesis contains 2 different variables, we cannot add them

Distribute (Multiply 3 by y and z)

3y + 3z

This is the simplest that this expression can get

Hope this helps :)

7 0

3 years ago