V =
![\pi \pi](https://tex.z-dn.net/?f=%20%5Cpi%20%5Cpi%20)
![r^{2}](https://tex.z-dn.net/?f=%20r%5E%7B2%7D)
h
1. Find the radius.
8/2 = 4
2. Square the radius.
![4^{2}](https://tex.z-dn.net/?f=%204%5E%7B2%7D%20)
= 16
3. Multiply that by pi.
3.14 * 16 = 50.24
4. Multiply that by the height.
50.24 * 20 = 1004.8
5. Now find 60% of that.
1004.8 * 0.6 = 602.88
V = 602.88
![m^{3}](https://tex.z-dn.net/?f=%20m%5E%7B3%7D)
Honestly, it's been a while since I've done this, but I believe this is the answer.
Answer:
13/30
Step-by-step:
First, you find the common denominator, which is 30. For the first fraction, multiply the bottom by five. Since you do that, you have to multiple the top by 5 as well, giving you 25/30. For the second problem, you multiple the top and bottom by six giving you 12/30. 25 minus 12 is 13 so you get 13/30.
Answer:
It is an identity, the proof is in the explanation
Step-by-step explanation:
csc(A)-cot(A)=tan(A/2)
I'm going to start with right hand side
tan(A/2)=(1-cos(a))/(sin(a)) half angle identity
tan(A/2)=1/sin(a)-cos(a)/sin(a) separate fraction
tan(A/2)=csc(a)-cot(a) reciprocal and quotient identities
It’s a function because the number doesn’t repeat