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Alja [10]
2 years ago
13

X²+5x+6 factorsing quadratic expressions ​

Mathematics
1 answer:
zhenek [66]2 years ago
7 0

Answer:

Times to get 6

Adds to get 5

2x3=6

2+3=5

(x+2)(x+3)

Or

(x+3)(x+2)

It's still the same

Hope this helps!

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Factor 3xy+21x+9 completely
inn [45]

Answer:

<h2>Hence the second option is the correct answer</h2>

Step-by-step explanation:

In this problem we are required to factor out the given terms as stated in the expression, what is obtainable is that we look for terms(greatest terms) that are common to all the terms in the expression and factor it out.

here is a way to do it

given the following expression

3xy+21x+9

From the expression above we can see that 3 is common to all the terms of the expression so that we have

3(xy+7x+3)

hence the second option is the correct answer

3 0
3 years ago
If the smallest of three consecutive numbers is k, write the expression for their sum.
omeli [17]
If they are three consecutive integers then they are:

k, k+1, and k+2 and the sum would then be:

s=k+k+1+k+2

s=3k+3
5 0
3 years ago
5 is what percent of 23
Eddi Din [679]
5 = what percent of 23

5 = x% of 23

5 = (x/100)*23

5 = 23x/100

5*100 = 23x

23x = 5*100

x = 5*100/23

x = 21.739

5 is ≈ 21.739% of 23 
8 0
3 years ago
What is <br> 8v+w+7−8v+2w
Bingel [31]

Answer:

3w+7

Step-by-step explanation:

Let's simplify step-by-step.

8v+w+7−8v+2w

=8v+w+7+−8v+2w

Combine Like Terms:

=8v+w+7+−8v+2w

=(8v+−8v)+(w+2w)+(7)

=3w+7

3 0
3 years ago
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1/25 i don’t know if this is right but here you go
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