Answer:
The answer is 53 or Square Root (sqrt) of 2809
Step-by-step explanation:
a^2+b^2=c^2
28^2+45^2=c^2
784+2025=c^2
c^2=sqrt 2809
c = 53
Answer:
8.1 x 10^-3 is the scientific notation form of 0.0081
Answer:
current volume of the water = 785.714 in²
Height of new container = 10 inches
Step-by-step explanation:
Radius of the container = 5 inches
Height of the container = 20 inches
Volume of the container = πR²H = (22/7) × 5² × 20 = 1571.428571428 in²
Since the container is half filled with water, volume of the water = 1571.428571428 ÷ 2 = 785.714 in²
b. Volume of cylinder = πR²H = volume of water from first container = 785.714 in²
Hence 785.714 = (22/7) × 5² × H
H = (785.714) ÷ [(22/7) × 25] = 10 inches
Height of new container = 10 inches
Given:
The two vectors are:
To find:
The value of 
.
Solution:
We have,
The cross product of these two vectors is:
![\overrightarrow{a}\times \overrightarrow{b}=\hat{i}[(-1)(5)-(1)(-3)]-\hat{j}[(2)(5)-(1)(1)]+\hat{k}[(2)(-3)-(-1)(1)]](https://tex.z-dn.net/?f=%5Coverrightarrow%7Ba%7D%5Ctimes%20%5Coverrightarrow%7Bb%7D%3D%5Chat%7Bi%7D%5B%28-1%29%285%29-%281%29%28-3%29%5D-%5Chat%7Bj%7D%5B%282%29%285%29-%281%29%281%29%5D%2B%5Chat%7Bk%7D%5B%282%29%28-3%29-%28-1%29%281%29%5D)
![\overrightarrow{a}\times \overrightarrow{b}=\hat{i}[-5+3]-\hat{j}[10-1]+\hat{k}[-6+1]](https://tex.z-dn.net/?f=%5Coverrightarrow%7Ba%7D%5Ctimes%20%5Coverrightarrow%7Bb%7D%3D%5Chat%7Bi%7D%5B-5%2B3%5D-%5Chat%7Bj%7D%5B10-1%5D%2B%5Chat%7Bk%7D%5B-6%2B1%5D)
Now the magnitude of the cross product is:
Therefore, the value of is 
.
