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2 years ago

I WILL CHOOSE BRAINLIEST!!!

Mathematics

1 answer:

sergejj [24]2 years ago

5 0

Answer:

13.8

Step-by-step explanation:

the required constant can be calculated as:

$c=\frac{FinalWages-InitialWages}{FinalTime-InitialTime} ;$

according to the formula above:

$c=\frac{82.8-27.6}{6-2} =13.8.$

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What is the domain of this table X 1 2 3 4 Y 2 4 3 2

Hoochie [10]

1,2,3,4 are the domain. The x column is always the domain.

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3 years ago

What the area of this shape is. Please help need to be down by tomorrow!!

puteri [66]

The area of this shape is 12.

Area of a triangle = 1/2 x bh

b= base

h = height

So,

1/2 (6)(4)=12

Hope this helps!

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2 years ago

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What is 8 + ¼ ÷ ⅖ using order of operations

Ksivusya [100]

Answer:

exact form: 69/8

mixed number form: 8 5/8

Step-by-step explanation:

1/4 ÷ 2/5 = 5/8 |

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2 years ago

Resolve into partial fractions 7-5x/2x^2+x-1

Flauer [41]

The decomposition of partial fractions is to start with the simplified reply and then take it apart, to "decompose" the final expression into its initial polynomial fractions.

Given:

$\to \bold{\frac{7-5x}{2x^2+x-1}}\\\\$

To find:

partial fractions=?

Solution:

$\to \bold{\frac{7-5x}{2x^2+x-1}}\\\\\to \bold{\frac{7-5x}{2x^2+x(2-1)-1}}\\\\\to \bold{\frac{7-5x}{2x^2+2x-x-1}}\\\\\to \bold{\frac{7-5x}{2x(x+1)-1(x+1)}}\\\\\to \bold{\frac{7-5x}{(2x-1)(x+1)} = \frac{A}{(2x-1)} - \frac{B}{(x+1)} }\\\\\to \bold{7-5x = \frac{A ((2x-1)(x+1))}{(2x-1)} - \frac{B((2x-1)(x+1))}{(x+1)} }\\\\\to \bold{7-5x = A(x+1) -B(2x-1) }\\\\$

putting $x=-1$

$\to \bold{7-5(-1) = A(-1+1) -B(2(-1)-1) }\\\\\to \bold{7+5 = A(0) -B(-2-1) }\\\\\to \bold{12 = +3B }\\\\\to \bold{B = \frac{12}{3} }\\\\\to \bold{B = 4 }\\\\$

putting $x= \frac{1}{2}$

$\to \bold{7-5(\frac{1}{2}) = A(\frac{1}{2}+1) -B(2(\frac{1}{2})-1) }\\\\\to \bold{7-\frac{5}{2} = A(\frac{3}{2}) -B((\frac{2}{2})-1) }\\\\\to \bold{7-\frac{5}{2} = A(\frac{3}{2}) -B(1-1) }\\\\\to \bold{\frac{14-5}{2} = A(\frac{3}{2}) -B(0) }\\\\\to \bold{\frac{9}{2} = A(\frac{3}{2})}\\\\\to \bold{\frac{9}{2} \times \frac{2}{3} = A}\\\\\to \bold{\frac{9}{3} = A}\\\\\to \bold{A=3}\\\\$

So, the final answer is " $\bold{\frac{7-5x}{(2x-1)(x+1)} = \frac{3}{(2x-1)} - \frac{4}{(x+1)} }\\\\$ ".

Learn more:

brainly.com/question/22286068

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3 years ago

What is the 222-5555

KiRa [710]

Are you trying to subtract?

If so, the answer is -5,333.

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3 years ago