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tia_tia [17]
2 years ago
10

From a plane flying due east at 265m above above sea level, the angle of depression from the plane to a ship is 25 degrees. How

far is the plane from the ship? Round to the nearest tenth of a foot.
Mathematics
1 answer:
Artyom0805 [142]2 years ago
8 0
627.0m the process is shown in the following picture.

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Express 110111 base two to base ten​
lidiya [134]

Answer:

zh

Step-by-step explanation:

4 0
3 years ago
I just need the answer
kumpel [21]

Answer:

it's B ;)

Step-by-step explanation:

A line segment has two endpoints; that is, it has a starting point and an ending point, much like a dead-end street. Bisector means to divide, not just in two, but in halves, or two equal parts. Therefore, a segment bisector is a point, a line, a ray, or a line segment that bisects another line segment.

6 0
3 years ago
Rule for raising a power to a new power
KiRa [710]
The practical rule would be, times that number, by the result of the first time you multiplied the first number. But, it would all depend by how much your're raising the number by.

<u>For example:</u> \boxed{4^6}

We do, (4*4*4*4*4*4)= \boxed{\bf{4^6}}= 4096

But, once again, this was an example. This would show and illustrate the rule of "raising a power".<span />
5 0
4 years ago
Find the area of the triangle with the given base and height.<br> b = 3 m and h = 10 1/2 m
svetoff [14.1K]

<u>Statement</u><u>:</u>

The base of a triangle is 3m and its height is 10 \frac{1}{2} m.

<u>To </u><u>find </u><u>out:</u>

The area of the triangle.

<u>Solution:</u>

  • Given, base = 3m, height = 10 \frac{1}{2}m
  • We know,

\sf \: area \:  \:  of \:  \: a \:  \: triangle =  \frac{1}{2}  \times base \:  \times height

  • Therefore, the area of the triangle

\sf =  (\frac{1}{2}  \times 3 \times 10 \frac{1}{2} ) {m}^{2}  \\ \sf  = ( \frac{1}{2}  \times 3 \times  \frac{21}{2} ) {m}^{2}  \\  = \sf  \frac{63}{4}  {m}^{2}  \\  =   \sf 15\frac{3}{4}  {m}^{2}

<u>Answer</u><u>:</u>

The area of the triangle is \sf \: 15 \frac{3}{4}  {m}^{2}

Hope you could understand.

If you have any query, feel free to ask.

5 0
3 years ago
Read 2 more answers
What is the horizontal asympote of this graph?
Anna35 [415]

Using it's concept, it is found that the graph has no horizontal asymptote.

<h3>What are the horizontal asymptotes of a function f(x)?</h3>

The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, we have that:

  • The function is undefined for x < 0, hence \lim_{x \rightarrow -\infty} f(x) is undefined.
  • For x > 0, the funciton goes to infinity, hence \lim_{x \rightarrow \infty} f(x) = \infty.

Thus, the graph has no horizontal asymptote.

More can be learned about horizontal asymptotes at brainly.com/question/16948935

#SPJ1

4 0
2 years ago
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