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bogdanovich [222]
2 years ago
13

Solve the equation.

="\sqrt{y^{2}-20+100 } =y-10" alt="\sqrt{y^{2}-20+100 } =y-10" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Lady bird [3.3K]2 years ago
6 0

Answer:

No solution.

Step-by-step explanation:

So lets solve the square root.

Sqrt(y^2 - 20 + 100) = y - 10

Sqrt(y^2 + 80 = y - 10)

Solve time.

y^2 + 80 = y - 10 (We are squaring them)

y^2 + 80 = y^2 - 20y + 100

y^2 + 80 - y^2 = y^2 - 20y + 100 - y^2 (Subtract y^2 from both sides)

80 = -20y + 100

Flip it

-20y + 100 = 80

-20y + 100 - 100 = 80 - 100 (Subtract 100 from both sides)

-20y = -20

Now divide both sides by -20

-20y/-20 = -20/-20

y = 1

All you would do is plug in the values and you get...

9 \neq -9

This is false.

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A trapezoid has an area of 80.75 sq. in., and its two bases are 7 and 12 inches long. Find the height of the trapezoid. a. 8.5 i
charle [14.2K]
<span>The formula is area of trapezoid = average base x average height 

We're going to do this in reverse.

Area = 80.75
[(7 + 12)/2] = 9.5 (height)
height = 80.75 / 9.5 = 8.5 

The height is 8.5, so the answer is D.</span>
5 0
4 years ago
Which line is parallel to the line that passes through the points (1, 7) and (-3, 4)?
Viktor [21]

Answer:

B

Step-by-step explanation:

The slope of the line that passes through the given points is (4-7)/(-3-1) = 3/4.

Since parallel lines have equivalent slopes, the answer is B.

5 0
2 years ago
Name the figure below in two different ways!<br> Need help fast!
kakasveta [241]

Answer:

IM  and  YM

Step-by-step explanation:

not sure about the symbol part, but it's a ray !!

4 0
2 years ago
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Identify the type of figure
AveGali [126]

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6 0
3 years ago
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the daily production cost, c, for x units is modeled by the equation: c = 200 – 7x 0.345x2 explain how to find the domain and ra
jenyasd209 [6]
C(x) = 200 - 7x + 0.345x^2

Domain is the set of x-values (i.e. units produced) that are feasible. This is all the positive integer values + 0, in case that you only consider that can produce whole units.

Range is the set of possible results for c(x), i.e. possible costs.

You can derive this from the fact that c(x) is a parabole and you can draw it, for which you can find the vertex of the parabola, the roots, the y-intercept, the shape (it open upwards given that the cofficient of x^2 is positive). Also limit the costs to be positive.

You can substitute some values for x to help you, for example:

x      y
0    200
1    200 -7 +0.345 = 193.345
2    200 - 14 + .345 (4) = 187.38
3    200 - 21 + .345(9) = 182.105
4    200 - 28 + .345(16) = 177.52
5    200 - 35 + 0.345(25) = 173.625
6    200 - 42 + 0.345(36) = 170.42

10  200 - 70 + 0.345(100) =164.5
11 200 - 77 + 0.345(121) = 164.745
 
 
The functions does not have real roots, then the costs never decrease to 0.

The function starts at c(x) = 200, decreases until the vertex, (x =10, c=164.5) and starts to increase.

Then the range goes to 164.5 to infinity, limited to the solutcion for x = positive integers.

6 0
4 years ago
Read 2 more answers
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