Write the equation for the function graphed below.

SAT

1 answer:

shusha [124]2 years ago

7 0

The equation of a line passing through (0, 0) and (2, 10) is y = 5x

<h3>Linear equation</h3>

A linear equation is in the form:

y = mx + b

where y, x are variables, m is the rate of change (slope of the line) and b is the y intercept.

Let us assume that the graph is a straight line passing through (0, 0) and (2, 10), hence:

$y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-0=\frac{10-0}{2-0} (x-0)\\\\y=5x$

The equation of a line passing through (0, 0) and (2, 10) is y = 5x

Find out more on Linear equation at: brainly.com/question/14323743

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What is the ph of a 0. 300 m solution of aniline (c₆h₅nh₂, kb = 4. 3 × 10⁻¹⁰)?.

yawa3891 [41]

The pH of the solution of aniline is; pH = 4.64

<h3>pH of aniline solution</h3>

According to the question;

We are required to determine the hydrogen ion concentration, pH of the given aniline solution.

Since, the given Kb is kb = 4. 3 × 10⁻¹⁰.

Hence, it follows that;

Ka = 10-¹⁴/4. 3 × 10⁻¹⁰.

Ka = 2.3 × 10⁻⁵.

On this note, the pH of aniline solution is;

pH = -log {2.3 × 10⁻⁵}

pH = 4.64.

Ultimately, the pH of the aniline solution given is; 4.64