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Paladinen [302]
2 years ago
5

Major has 25 free minutes left until he needs to head to tennis practice he already spent four of the minute playing a video gam

e what is the maximum number of minutes he can spend doing homework be for he needs to leave for practice
one step inequality word problems ​
Mathematics
1 answer:
Elan Coil [88]2 years ago
4 0

Answer:

ok so he has 25 minutes in total and then we need to subtract the time hes alredy used so

25-4=21

so he has 21 minutes to do homework

Hope This Helps!!!

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2/3 + 1/4 <br><br> Answers should be in the format 5/2 or 2/5 no decimals or mixed numbers
frutty [35]

Answer:

11/12

Step-by-step explanation:

2/3+1/4

8+3/12

=11/12

4 0
3 years ago
Make x the subject of m=n + x/p
marshall27 [118]

Answer:

\boxed{x = p(m - n)}

Step-by-step explanation:

=  > m = n +  \frac{x}{p}  \\  \\  =  > m = (n \times  \frac{p}{p} ) +  \frac{x}{p}  \\  \\  =  > m =  \frac{pn}{p}  +  \frac{x}{p}  \\  \\  =  > m =  \frac{pn + x}{p}  \\  \\  =  > mp = pn + x \\  \\  =  > x + pn = pm \\  \\  =  > x = pm - pn \\  \\  =  > x = p(m - n)

4 0
3 years ago
In ΔLMN, m = 390 cm, n = 430 cm and ∠L=134°. Find the length of l, to the nearest centimeter. PLEASE HELP ITS URGENT
BartSMP [9]

Answer:

755

Step-by-step explanation:

DeltaMath

3 0
3 years ago
find a set of parametric equations of the line the line pases through the point (2,3,4) and is parallel to the xz-plane and the
joja [24]

Answer:

x=2, y=3, z=4+t

Step-by-step explanation:

For this case we need a line parallel to the plane x z and yz. And by definition of parallel we see that the intersection between the xz and yz plane is the z axis. And we can take the following unitary vector to construct the parametric equations:

u= (u_x, u_y, u_z)= (0,0,1)

Or any factor of u but for simplicity let's take the unitary vector.

Then the parametric equations are given by:

x= P_x + u_x t

y= P_y + u_y t

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Where the point given P=(2,3,4)= (P_x , P_y, P_z)

And then since we have everything we can replace like this:

x= P_x + u_x t 2+ 0*t = 2

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z= P_z + u_z t = 4+ 1t = 4+t

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6 0
3 years ago
Find the distance between the points (4,-2) and (0,10)
vagabundo [1.1K]

We can solve this problem by using the distance formula. The distance formula is: \sqrt{(x_{1}-x)^{2} + (y_{1} - y)^{2}} We can now put in values and solve.

\sqrt{(4-0)^{2} + (-2-10)^{2}}  

\sqrt{16 + 144}

\sqrt{160} 

3 0
3 years ago
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