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3 years ago

How are the symbols for greater than (>) and greater than or equal to (≥) related?

Mathematics

2 answers:

netineya [11]3 years ago

7 0

Answer:

The greater than symbol is >. So, 9>7 is read as '9 is greater than 7'. The less than symbol is <. Two other comparison symbols are ≥ (greater than or equal to) and ≤ (less than or equal to).

Step-by-step explanation:

Ivan3 years ago

7 0

Answer:

it yo momma -2

Step-by-step explanation:

when your momma is 1 she is really -1

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Answer is C. 168 fluid ounces

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3 years ago

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Mrsjones has 1 4/8 pizza left after giving some to Greg she had 7/8 left how much did Greg take

Bezzdna [24]

Answer:

5/8

Step-by-step explanation:

well we 1 14/8 so lets turn that to a whole number which is 12/8 (you multiply the denominator by 1 and add the 4)

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3 years ago

.21 of what number is 7.98

AlladinOne [14]

.21 as a percentage is 21%
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Hope this helps :)

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3 years ago

Find the area of the trapezoid to the nearest tenth.

erica [24]

Answer:

2.2 metres squared

Step-by-step explanation:

We need to find the area of this trapezoid.

The area of a trapezoid is denoted by:

$A=\frac{(b_1+b_2)h}{2}$ , where $b_1$ and $b_2$ are the parallel bases and h is the height

Here, we already know the lengths of the two bases; they are 0.9 metres and 2.3 metres. However, we need to find the length of the height.

Notice that one of the angles is marked 45 degrees. Let's draw a perpendicular line from top endpoint of the segment labelled 0.9 to the side labelled 2.3. We now have a 45-45-90 triangle with hypotenuse 2.0 metres. As one of such a triangle's properties, we can divide 2.0 by √2 to get the length of both legs:

2.0 ÷ √2 = √2 ≈ 1.414 ≈ 1.4

Thus, the height is h = 1.4 metres. Now plug all these values we know into the equation to find the area:

$A=\frac{(b_1+b_2)h}{2}$

$A=\frac{(0.9+2.3)*1.4}{2}=2.2$

The answer is thus 2.2 metres squared.

<em>~ an aesthetics lover</em>

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3 years ago

Solve for y. 4y+5/3 = y-8/2 y = -4 y = -5 y = -8

horrorfan [7]

Answer:

Step-by-step explanation:

$\dfrac{4y+5}{3}=\dfrac{y-8}{2}\qquad\text{multiply both sides by }\ 2\cdot3=6\\\\6\!\!\!\!\diagup^2\cdot\dfrac{4y+5}{\not3_1}=6\!\!\!\!\diagup^3\cdot\dfrac{y-8}{\not2_1}\\\\2(4y+5)=3(y-8)\qquad\text{use distributive property}\\\\(2)(4y)+(2)(5)=(3)(y)+(3)(-8)\\\\8y+10=3y-24\qquad\text{subtract 10 from both sides}\\\\8y=3y-34\qquad\text{subtract 3y from both sides}\\\\5y=-34\qquad\text{divide both sides by 5}\\\\\boxed{y=-\dfrac{34}{5}}$

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3 years ago