An arithmetic sequence is one where each term is a constant difference, called the common difference, from the preceding term. The arithmetic sequence can always be expressed as:
a(n)=a+d(n-1), a=first term, d=common difference, n=term number.
We are given two terms and term numbers, so we can solve for the common difference...
101=5+d(25-1)
101=5+25d-d
101=5+24d
96=24d
d=4
So the common difference is 4.
Answer:
Step-by-step explanation:
Factor it by first setting it equal to 0:
Now subtract 9 from both sides:
Divide both sides by 4:
Then take the square root of both sides:
x = ±
, which of course is not allowed. Therefore, we have to allow for the imaginary numbers in this solution. Knowing that,
x = ±
is an equivalent radicand, we can now replace -1 with its imaginary counterpart:
x = ±
Each one of the elements in the radicand are perfect squares, so we simplify as follows:
x = ±
And there you go!
Answer:
no
Step-by-step explanation:
no because 29 is a prime number, meaning its only factors are 1 and 29. if you were to have more than 1 book on each shelf then you would go into half and quarters of books.
The price for senior citizens was 4 dollars and the price for the child tickets would be 7 dollars.
It will take her 54 days to take 10 more tests
