Answer:
What else is produced during the replacement reaction of silver nitrate and potassium sulfate? 2AgNO3 K2SO4 → Ag2SO4+2KNO3
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B.angela avoids using any of ha friend's personal items at school
The answer to this is systematic musicology. (:
Answer:
Answer:
Stabilizer with area = 14 cm².
Step-by-step explanation:
Area of the wing = 101.25 cm²
Rule of the thumb is that area of stabilizer must be about 1/6 to 1/8 of the area of wing. So, first we calculate 1/6 of the area of the wing and 1/8 of the area of the wing. Area of stabilizer must be in between these two numbers.
1/6 of the area of wing = \frac{1}{6} \times 101.25 = 16.87561×101.25=16.875
1/8 of the area of wing = \frac{1}{8} \times 101.25 = 12.65681×101.25=12.656
This means, the area of horizontal stabilizer must be in between 12.656 cm² and 16.875 cm². From the given options only one option lies in between these two numbers and that is 14 cm²
Therefore, area of a good stabilizer design from the given options would be 14 cm²
