Answer:
see explanation
Explanation:
(a)
3x + 5y = 8 → (1)
4x - 3y = 1 → (2)
multiplying (1) by 3 and (2) by 5 and adding the result will eliminate y
9x + 15y = 24 → (3)
20x - 15y = 5 → (4)
add (3) and (4) term by term to eliminate y
29x + 0 = 29
29x = 29 ( divide both sides by 29 )
x = 1
substitute x = 1 into either of the 2 equations and solve for y
substituting into (1)
9(1) + 15y = 24
9 + 15y = 24 ( subtract 9 from both sides )
15y = 15 ( divide both sides by 15 )
y = 1
solution is x = 1 , y = 1
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(b)
6p + 4q = 20 → (1)
5p - 2q = 6 → (2)
multiplying (2) by 2 and adding to (1) will eliminate q
10p - 4q = 12 → (3)
add (1) and (3) term by term to eliminate q
16p + 0 = 32
16p = 32 ( divide both sides by 16 )
p = 2
substitute p = 2 into either of the 2 equations and solve for q
substituting into (1)
6(2) + 4q = 20
12 + 4q = 20 ( subtract 12 from both sides )
4q = 8 ( divide both sides by 4 )
q = 2
solution is p = 2 , q = 2
