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alex41 [277]
3 years ago
14

Math work pls help .........​

Mathematics
2 answers:
Setler [38]3 years ago
4 0

Answer:

2z^3\sqrt{14z}

Step-by-step explanation:

\sqrt{56z^7}\\ \sqrt{4*14*z^6*z}\\2 z^3\sqrt{14z}

Lorico [155]3 years ago
4 0

Answer:

\sqrt{4}\sqrt{z^2}\sqrt{z^2}\sqrt{z^2}

Step-by-step explanation:

\sqrt{56z^7} = \sqrt{4}\sqrt{14}\sqrt{z^2}\sqrt{z^2}\sqrt{z^2}\sqrt{z}

the perfect squares are:

\sqrt{4}\sqrt{z^2}\sqrt{z^2}\sqrt{z^2} = 2z³

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