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Daniel [21]
3 years ago
13

4x^2+2x-5-3x and 6x^2-x+3-2x^2-8 Are these two expressions equal? Show how you know

Mathematics
2 answers:
aivan3 [116]3 years ago
7 0

Step-by-step explanation:

Simply Equation 1

R. H. S

6x^2 -x +3-2x^2-8

==> 6x^2-2x^2 -x +3-8

==> 4x^2-x-5 .....(1)

Simply equation 2

L. H. S

4x^2+2x-5-3x

==> 4x^2 +2x-3x-5

==> 4x^2-x-5 ....(2)

Since here, RHS = LHS

both eqn (1) = eqn(2)

hence they are equal.

PtichkaEL [24]3 years ago
4 0

Answer:

yes they are equal

Step-by-step explanation:

for the equation 4x^{2} +2x-5-3x you're going to collect like terms

2x-3x=5x

so your final equation is 4x^{2} -x-5

for the equation 6x^{2} -x+3-2x^{2} -8 you're going to collect like terms

6x^{2} -2x^{2} =4x^{2}

then you're going to calculate the difference

3x-8=-5

so your final equation is 4x^{2} -x-5

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Bingel [31]

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3 years ago
How many integers satisfy each inequality? <br>-102
olga55 [171]

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Step-by-step explanation:

7 0
3 years ago
A cable installer charges 42.50 per hour plus a 45.00 service charge. your fathers firm hires him to hook up his company's inter
Brilliant_brown [7]
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8 0
3 years ago
A student finds a positive correlation between the number of beds in a home and the number of plates in the kitchen.
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3 0
3 years ago
Read 2 more answers
What is the volume of the box with a square base
Deffense [45]

We must find the volume of a box with:

• square base with diagonal ,h = 6 cm,,

,

• height ,H = 15 cm,.

1) First we compute the length of the sides of the square base.

From the diagram above, we see that the diagonal of the box constitutes the hypotenuse of a triangle of sides a. Pitagoras Theorem states that the square of the hypotenuse is equal to the sum of the squares of the other sides, so we have:

h^2=a^2+a^2=2a^2\text{.}

Replacing the value h = 6 cm, and solving for a², we get:

\begin{gathered} (6\operatorname{cm})^2=2a^2, \\ 36cm^2=2a^2, \\ a^2=\frac{36cm^2}{2}, \\ a^2=18cm^2\text{.} \end{gathered}

2) The volume is given by the product of height (H) and the area of the base (a²):

V=H\cdot a^2=15\operatorname{cm}\cdot18cm^2=270cm^3.

Answer

The volume of the box is 270 cm³.

5 0
2 years ago
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