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leonid [27]
3 years ago
13

The volumes of two similar figures are 343 mm3 and 512 mm3. If the surface area of the larger figure is 192 mm2, what is the sur

face area of the smaller figure?
Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
5 0

Answer:

the smaller figure is 147 mm².

Kobotan [32]3 years ago
3 0
In geometry, similar figures are those whose ratios of the  corresponding sides are equal and the corresponding  angles are congruent. In relation to the volume, we determine first the cube roots of the given and find the ratio as shown below.
 
                         s1 / s2 = cube root of (512/343)
                                    = 8/7
The square of this ratio is the ratio of the areas of the figure. If we let x be the area of the smaller figure then, 
                      (8/7)^2 = 192 mm²/ x
The value of x from the equation is 147 mm². 

The area therefore of the smaller figure is 147 mm².
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Answer:below hopes it helps the link should help aswell

Step-by-step explanation:

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3 0
3 years ago
6 (3x-1)-10x. with work please :)
STatiana [176]
Hey there!
Let's break this expression into two parts:
6(3x-1) and -10x

To solve the first part, we need to use the distributive property which states:
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Applying that to this problem, we have:
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Now, we can take that -10x and put it right back in:

18x - 6 - 10x

Combine like terms and subtract the 10x from the 18x to get:
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Hope this helps!
4 0
3 years ago
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Karolina [17]
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4 years ago
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White raven [17]

Answer:

A

Step-by-step explanation:

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So you times Pie by the radius (diametre divided by two- 3.5) you then square this. After that, times it by the height (10)

So the volume is 384.85.

You then find 30% of this, so times 384.85 by 30%.

You then get an answer of 115.455, and this is equal to A.

I hope this helps, have a lovely day.

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