Eighteen percent of apples grown in an orchard have defects. Let X = the number of apples that are randomly inspected from the o
rchard until a defective one is found.
What is P(X ≤ 4)?
Round to 3 decimal places.
1 answer:
Answer:
0.219 or 21.028%
Step-by-step explanation:
0.18 are defective, so
P(x=1) = 0.18
P(x=2) = 0.18^2 = 0.0324
P(x=3) = 0.18^3 = 0.005832
P(x=4) = 0.18^4 = 0.00104976
Then add them together: 0.21928176
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